postgres.git / summary / log / commit / refs
commit 4bc6fb57f774ea18187fd8565aad9994160bfc17
Author: Heikki Linnakangas <heikki.linnakangas@iki.fi>
Date: Tue May 29 19:22:43 2012 +0000
First released in: 9.2.0
Fix integer overflow bug in GiST buffering build calculations.
The result of (maintenance_work_mem * 1024) / BLCKSZ doesn't fit in a signed
32-bit integer, if maintenance_work_mem >= 2GB. Use double instead. And
while we're at it, write the calculations in an easier to understand form,
with the intermediary steps written out and commented.
src/backend/access/gist/gistbuild.c | 32 +++++++++++++++++++++++---------
1 file changed, 23 insertions(+), 9 deletions(-)
diff --git a/src/backend/access/gist/gistbuild.c b/src/backend/access/gist/gistbuild.c
index 988896d289f..eb39c667c15 100644
--- a/src/backend/access/gist/gistbuild.c
+++ b/src/backend/access/gist/gistbuild.c
@@ -323,8 +323,8 @@ gistInitBuffering(GISTBuildState *buildstate)
* calculating levelStep is very close to Arge et al's formula. For a
* large B, our formula gives a value that is 2x higher.
*
- * The average size of a subtree of depth n can be calculated as a
- * geometric series:
+ * The average size (in pages) of a subtree of depth n can be calculated
+ * as a geometric series:
*
* B^0 + B^1 + B^2 + ... + B^n = (1 - B^(n + 1)) / (1 - B)
*
@@ -353,14 +353,28 @@ gistInitBuffering(GISTBuildState *buildstate)
* the hash table.
*/
levelStep = 1;
- while (
- /* subtree must fit in cache (with safety factor of 4) */
- (1 - pow(avgIndexTuplesPerPage, (double) (levelStep + 1))) / (1 - avgIndexTuplesPerPage) < effective_cache_size / 4
- &&
- /* each node in the lowest level of a subtree has one page in memory */
- (pow(maxIndexTuplesPerPage, (double) levelStep) < (maintenance_work_mem * 1024) / BLCKSZ)
- )
+ for (;;)
{
+ double subtreesize;
+ double maxlowestlevelpages;
+
+ /* size of an average subtree at this levelStep (in pages). */
+ subtreesize =
+ (1 - pow(avgIndexTuplesPerPage, (double) (levelStep + 1))) /
+ (1 - avgIndexTuplesPerPage);
+
+ /* max number of pages at the lowest level of a subtree */
+ maxlowestlevelpages = pow(maxIndexTuplesPerPage, (double) levelStep);
+
+ /* subtree must fit in cache (with safety factor of 4) */
+ if (subtreesize > effective_cache_size / 4)
+ break;
+
+ /* each node in the lowest level of a subtree has one page in memory */
+ if (maxlowestlevelpages > ((double) maintenance_work_mem * 1024) / BLCKSZ)
+ break;
+
+ /* Good, we can handle this levelStep. See if we can go one higher. */
levelStep++;
}
[parent: 2755abf386e6]