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SQL statement form shell ?
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* SQL statement form shell ?
@ 2014-08-27 15:04 czezz <czezz@o2.pl>
  2014-08-27 15:13 ` Re: SQL statement form shell ? Raghavendra <raghavendra.rao@enterprisedb.com>
  2014-08-27 15:30 ` Re: SQL statement form shell ? Scott Whitney <scott@journyx.com>
  0 siblings, 2 replies; 7+ messages in thread

From: czezz @ 2014-08-27 15:04 UTC (permalink / raw)
  To: pgsql-admin

Im trying to execute simple query in shell. 
This query works OK in PSQL client: 
Server4=# SELECT * FROM foo2;

However, for some reason I cannot execute it in shell. I try it like following:

-bash-4.1$ psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM foo2;"
ERROR:  relation "foo2" does not exist
LINE 1: SELECT * FROM foo2;
                      ^

Any ideas what Im doing wrong ?

BR,
czezz


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^ permalink  raw  reply  [nested|flat] 7+ messages in thread

* Re: SQL statement form shell ?
  2014-08-27 15:04 SQL statement form shell ? czezz <czezz@o2.pl>
@ 2014-08-27 15:13 ` Raghavendra <raghavendra.rao@enterprisedb.com>
  2014-08-27 15:23   ` Re:  SQL statement form shell ? czezz <czezz@o2.pl>
  1 sibling, 1 reply; 7+ messages in thread

From: Raghavendra @ 2014-08-27 15:13 UTC (permalink / raw)
  To: czezz <czezz@o2.pl>; +Cc: pgsql-admin

Is the database name correct ?
In your OK execution, database looks to be "Server4" and in other execution
its "fm_db_Server4".


---
Regards,
Raghavendra
EnterpriseDB Corporation
Blog: http://raghavt.blogspot.com/


On Wed, Aug 27, 2014 at 8:34 PM, czezz <czezz@o2.pl> wrote:

> Im trying to execute simple query in shell.
> This query works OK in PSQL client:
> Server4=# SELECT * FROM foo2;
>
> However, for some reason I cannot execute it in shell. I try it like
> following:
>
> -bash-4.1$ psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM foo2;"
> ERROR:  relation "foo2" does not exist
> LINE 1: SELECT * FROM foo2;
>                       ^
>
> Any ideas what Im doing wrong ?
>
> BR,
> czezz
>
>
> --
> Sent via pgsql-admin mailing list (pgsql-admin@postgresql.org)
> To make changes to your subscription:
> http://www.postgresql.org/mailpref/pgsql-admin
>

^ permalink  raw  reply  [nested|flat] 7+ messages in thread

* Re:  SQL statement form shell ?
  2014-08-27 15:04 SQL statement form shell ? czezz <czezz@o2.pl>
  2014-08-27 15:13 ` Re: SQL statement form shell ? Raghavendra <raghavendra.rao@enterprisedb.com>
@ 2014-08-27 15:23   ` czezz <czezz@o2.pl>
  2014-08-27 16:43     ` Re: SQL statement form shell ? Raghavendra <raghavendra.rao@enterprisedb.com>
  0 siblings, 1 reply; 7+ messages in thread

From: czezz @ 2014-08-27 15:23 UTC (permalink / raw)
  To: Raghavendra <raghavendra.rao@enterprisedb.com>; +Cc: pgsql-admin

Copy/Paste error. DB name should be: fm_db_Server4
Dnia 27 sierpnia 2014 17:13 Raghavendra &lt;raghavendra.rao@enterprisedb.com&gt; napisał(a):
fm_db_Server4

^ permalink  raw  reply  [nested|flat] 7+ messages in thread

* Re: SQL statement form shell ?
  2014-08-27 15:04 SQL statement form shell ? czezz <czezz@o2.pl>
  2014-08-27 15:13 ` Re: SQL statement form shell ? Raghavendra <raghavendra.rao@enterprisedb.com>
  2014-08-27 15:23   ` Re:  SQL statement form shell ? czezz <czezz@o2.pl>
@ 2014-08-27 16:43     ` Raghavendra <raghavendra.rao@enterprisedb.com>
  2014-08-27 16:50       ` Re: SQL statement form shell ? Scott Whitney <scott@journyx.com>
  0 siblings, 1 reply; 7+ messages in thread

From: Raghavendra @ 2014-08-27 16:43 UTC (permalink / raw)
  To: czezz <czezz@o2.pl>; +Cc: pgsql-admin

On Wed, Aug 27, 2014 at 8:53 PM, czezz <czezz@o2.pl> wrote:

> Copy/Paste error. DB name should be: fm_db_Server4
>
>
> ​
​Did you set
PGOPTIONS environment variable for that terminal for any specific schema
which do not contain the table "foo"
​. Then you might hit the error

-bash-4.1$ export PGOPTIONS="-c search_path=tester"
-bash-4.1$ psql -p 5432 -d postgres -c "SELECT * FROM foo;"
ERROR:  relation "foo" does not exist
LINE 1: SELECT * FROM foo;
                      ^
​
​---
Regards,
Raghavendra
EnterpriseDB Corporation
Blog: http://raghavt.blogspot.com/



>
> Dnia 27 sierpnia 2014 17:13 Raghavendra <raghavendra.rao@enterprisedb.com>
> napisał(a):
>
> fm_db_Server4
>
>
>
>

^ permalink  raw  reply  [nested|flat] 7+ messages in thread

* Re: SQL statement form shell ?
  2014-08-27 15:04 SQL statement form shell ? czezz <czezz@o2.pl>
  2014-08-27 15:13 ` Re: SQL statement form shell ? Raghavendra <raghavendra.rao@enterprisedb.com>
  2014-08-27 15:23   ` Re:  SQL statement form shell ? czezz <czezz@o2.pl>
  2014-08-27 16:43     ` Re: SQL statement form shell ? Raghavendra <raghavendra.rao@enterprisedb.com>
@ 2014-08-27 16:50       ` Scott Whitney <scott@journyx.com>
  0 siblings, 0 replies; 7+ messages in thread

From: Scott Whitney @ 2014-08-27 16:50 UTC (permalink / raw)
  To: Raghavendra <raghavendra.rao@enterprisedb.com>; +Cc: czezz <czezz@o2.pl>; pgsql-admin

Also, throughout this thread, you have given us 2 separate ports: 5472 and 5432 (default). 

In _this_ example, you set the database to "postgres," not to "Server4," as well. 
Then there's that whole "foo," versus "foo2," thing going on... 

There are a lot of differences in what you have sent over the course of this thread. 

I would back up, take a deep breath, and start over. 

1) Connect to your database something like this: 
psql ___name of database___ 

2) SELECT * from "foo2"; 

3) Does that work? Once you make that work, proceed to test from the command line like this: 

psql ___name of database__ -c "SELECT * from \"foo2\" ; " 

If you make 1 and 2 work, 3 should work. BUT ALL OF THE OPTIONS HAVE TO BE THE SAME. 
You cannot select * from foo in steps 1 and 2 and select * from foo2 in step 3. 
You cannot use port 5472 in step 1/2 and 5432 in step 3. 
You cannot connect to the db postgres in steps 1/2 and another db in step 3. 

That invalidates your process. 

----- Original Message -----

> On Wed, Aug 27, 2014 at 8:53 PM, czezz < czezz@o2.pl > wrote:

> > Copy/Paste error. DB name should be: fm_db_Server4
> 

> ​
> ​Did you set
> PGOPTIONS environment variable for that terminal for any specific schema
> which do not contain the table "foo"
> ​. Then you might hit the error

> -bash-4.1$ export PGOPTIONS="-c search_path=tester"
> -bash-4.1$ psql -p 5432 -d postgres -c "SELECT * FROM foo;"
> ERROR: relation "foo" does not exist
> LINE 1: SELECT * FROM foo;
> ^
> ​
> ​---
> Regards,
> Raghavendra
> EnterpriseDB Corporation
> Blog: http://raghavt.blogspot.com/

> > Dnia 27 sierpnia 2014 17:13 Raghavendra < raghavendra.rao@enterprisedb.com
> > >
> > napisał(a):
> 

> > > fm_db_Server4
> > 
>
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Austin, TX 78757
www.journyx.com

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f 512.834.8858
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^ permalink  raw  reply  [nested|flat] 7+ messages in thread

* Re: SQL statement form shell ?
  2014-08-27 15:04 SQL statement form shell ? czezz <czezz@o2.pl>
@ 2014-08-27 15:30 ` Scott Whitney <scott@journyx.com>
  2014-08-28 08:19   ` Re:  SQL statement form shell ? czezz <czezz@o2.pl>
  1 sibling, 1 reply; 7+ messages in thread

From: Scott Whitney @ 2014-08-27 15:30 UTC (permalink / raw)
  To: czezz <czezz@o2.pl>; +Cc: pgsql-admin

There are a few things I would check. 

a) psql -p 5472 -d fm_db_Server4 
b) SELECT * from foo2; 
c) Do those _2_ statements work separately? That should prove that you're talking to the exact same connection/host/port you expect. 
d) psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM foo2; 

So, step a&b succeed, but step d fails? 

d) psql -p 5472 -d fm_db_Server4 
e) SELECT * from "foo2"; 

If this doesn't work, "foo2," is not a valid relation. It's case-sensitive or some such. Once you can make the table name work within " " marks, THEN try from the command prompt like: 

f) psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM \"foo2\" ; " 

----- Original Message -----

> Im trying to execute simple query in shell.
> This query works OK in PSQL client:
> Server4=# SELECT * FROM foo2;

> However, for some reason I cannot execute it in shell. I try it like
> following:

> -bash-4.1$ psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM foo2;"
> ERROR: relation "foo2" does not exist
> LINE 1: SELECT * FROM foo2;
> ^

> Any ideas what Im doing wrong ?

> BR,
> czezz

> --
> Sent via pgsql-admin mailing list (pgsql-admin@postgresql.org)
> To make changes to your subscription:
> http://www.postgresql.org/mailpref/pgsql-admin

Journyx, Inc.
7600 Burnet Road #300
Austin, TX 78757
www.journyx.com

p 512.834.8888
f 512.834.8858
Do you receive our promotional emails? You can subscribe or unsubscribe to those emails at http://go.journyx.com/emailPreference/e/4932/714

^ permalink  raw  reply  [nested|flat] 7+ messages in thread

* Re:  SQL statement form shell ?
  2014-08-27 15:04 SQL statement form shell ? czezz <czezz@o2.pl>
  2014-08-27 15:30 ` Re: SQL statement form shell ? Scott Whitney <scott@journyx.com>
@ 2014-08-28 08:19   ` czezz <czezz@o2.pl>
  0 siblings, 0 replies; 7+ messages in thread

From: czezz @ 2014-08-28 08:19 UTC (permalink / raw)
  To: Scott Whitney <swhitney@journyx.com>; Scott Whitney <scott@journyx.com>; +Cc: pgsql-admin; raghavendra.rao@enterprisedb.com; payal@omniti.co

Hi,
I think I got it.
It seems that I need to indicate specific user name and only then the query works.
-bash-4.1$ psql -p 5472 -d fm_db_Server4 -U msuper -c "SELECT * FROM foo2;"
Im new to postgresql but I guess -U (user) also somehow defines tablespace where specific table is created.
Anyway, thank you all for your help and answers.
Cheers,
czezz
Dnia 27 sierpnia 2014 17:30 Scott Whitney &lt;scott@journyx.com&gt; napisał(a):
There are a few things I would check. a) psql -p 5472 -d fm_db_Server4b) SELECT * from foo2;c) Do those _2_ statements work separately? That should prove that you're talking to the exact same connection/host/port you expect.d) psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM foo2; So, step a&amp;b succeed, but step d fails? d) psql -p 5472 -d fm_db_Server4e) SELECT * from "foo2";
 If this doesn't work, "foo2," is not a valid relation. It's case-sensitive or some such. Once you can make the table name work within " " marks, THEN try from the command prompt like: f) psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM \"foo2\" ; "  Im trying to execute simple query in shell.
This query works OK in PSQL client:
Server4=# SELECT * FROM foo2;
 However, for some reason I cannot execute it in shell. I try it like following:
 -bash-4.1$ psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM foo2;"
ERROR:  relation "foo2" does not exist
LINE 1: SELECT * FROM foo2;
                      ^
 Any ideas what Im doing wrong ?
 BR,
czezz
 
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To make changes to your subscription:
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 Journyx, Inc.7600 Burnet Road #300
Austin, TX 78757
www.journyx.com p 512.834.8888 f 512-834-8858  Do you receive our promotional emails? You can subscribe or unsubscribe to those emails here. 

^ permalink  raw  reply  [nested|flat] 7+ messages in thread


end of thread, other threads:[~2014-08-28 08:19 UTC | newest]

Thread overview: 7+ messages (download: mbox mbox.gz follow: Atom feed)
-- links below jump to the message on this page --
2014-08-27 15:04 SQL statement form shell ? czezz <czezz@o2.pl>
2014-08-27 15:13 ` Raghavendra <raghavendra.rao@enterprisedb.com>
2014-08-27 15:23   ` czezz <czezz@o2.pl>
2014-08-27 16:43     ` Raghavendra <raghavendra.rao@enterprisedb.com>
2014-08-27 16:50       ` Scott Whitney <scott@journyx.com>
2014-08-27 15:30 ` Scott Whitney <scott@journyx.com>
2014-08-28 08:19   ` czezz <czezz@o2.pl>

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