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From: Adrian Klaver <[email protected]>
To: Colin 't Hart <[email protected]>
To: [email protected]
Subject: Re: Regression in Postgres 17?
Date: Tue, 22 Oct 2024 09:03:05 -0700
Message-ID: <[email protected]> (raw)
In-Reply-To: <CAMon-aR07TWHZt2QX9QsZQEniyE-6+FdHJSGwyMwvegJSjjNug@mail.gmail.com>
References: <CAMon-aR07TWHZt2QX9QsZQEniyE-6+FdHJSGwyMwvegJSjjNug@mail.gmail.com>

On 10/22/24 08:54, Colin 't Hart wrote:
> Hi,
> 
> This works in Postgres 15:
> 
> pg15> create function json_test(out value text, out json jsonb)
> returns record
> language sql
> as
> $$
>    select null::text, null::jsonb;
> $$
> ;
> CREATE FUNCTION
> pg15> select * from json_test();
> ┌───────┬──────┐
> │ value │ json │
> ├───────┼──────┤
> │       │      │
> └───────┴──────┘
> (1 row)
> 
> 
> In Postgres 17 trying to create the function yields an error:
> 
> pg17> create function json_test(out value text, out json jsonb)
> returns record
> language sql
> as
> $$
>    select null::text, null::jsonb;
> $$
> ;
> ERROR:  syntax error at or near "jsonb"
> LINE 1: create function json_test(out value text, out json jsonb)
> 
> 
> Am I doing something wrong? Or is this a regression?

Yes you are doing something wrong, naming an argument with a type 
name(json) is not a good idea. Guessing you got caught by this:

https://www.postgresql.org/docs/16/sql-keywords-appendix.html

JSON 	non-reserved 	reserved 	  	

https://www.postgresql.org/docs/17/sql-keywords-appendix.html

JSON 	non-reserved (cannot be function or type) 	reserved 	  	



> Thanks,
> 
> Colin

-- 
Adrian Klaver
[email protected]

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