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help / color / mirror / Atom feedFrom: Ron Johnson <[email protected]>
To: pgsql-general <[email protected]>
Subject: psql: print values and return the COUNT(*) value to bash?
Date: Mon, 29 Dec 2025 02:21:41 -0500
Message-ID: <CANzqJaBX-SZZcHn71xgqtSKx6ekZGdHPSgCmP2co5=-KDu4Q-Q@mail.gmail.com> (raw)
Currently I do this in a bash script:
Tbl=table_1
Fld=field_1
Sql="SELECT CURRENT_TIMESTAMP - MIN($Fld) AS days_ago
, MIN($Fld) as oldest_date
, COUNT(*) AS cnt
FROM $Tbl;"
psql -h <host> <db> -Xc "${Sql}"
days_ago | oldest_date | cnt
----------+-------------+-----
| | 0
(1 row)
More stuff happens after this. I want to print out these four lines, but
also test the COUNT(*) value and bypass other bash commands if the count ==
0.
Is there any relatively simple way to do this (psql print and return
count(*))?
--
Death to <Redacted>, and butter sauce.
Don't boil me, I'm still alive.
<Redacted> lobster!
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Subject: Re: psql: print values and return the COUNT(*) value to bash?
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