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From: vignesh C <[email protected]>
To: Shlok Kyal <[email protected]>
Cc: Álvaro Herrera <[email protected]>
Cc: Sergey Tatarintsev <[email protected]>
Cc: [email protected]
Subject: Re: Restrict publishing of partitioned table with a foreign table as partition
Date: Mon, 17 Feb 2025 20:12:49 +0530
Message-ID: <CALDaNm2+eL22Sbvj74uS37xvt=haQWcOwP15QnDuVeYsjHiffw@mail.gmail.com> (raw)
In-Reply-To: <CANhcyEWYJccdE0VP7dnMXGXvM3Lp5em_27hBu3tvi5N3=nWohg@mail.gmail.com>
References: <CALDaNm0EA4zuR+PiNmADGORcADQsPSmYKo=tr4hT=pSrLY1B9A@mail.gmail.com>
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On Fri, 14 Feb 2025 at 12:59, Shlok Kyal <[email protected]> wrote:
>
> I have used the changes suggested by you. Also I have updated the
> comments and the function name.

There is another concurrency issue possible:
+/* Check if a partitioned table has a foreign partition */
+bool
+check_partrel_has_foreign_table(Form_pg_class relform)
+{
+       bool            has_foreign_tbl = false;
+
+       if (relform->relkind == RELKIND_PARTITIONED_TABLE)
+       {
+               List       *relids = NIL;
+
+               relids = find_all_inheritors(relform->oid, NoLock, NULL);

Create a publication with publish_via_partition_root as true, hold the
execution after check_partrel_has_foreign_table execution finishes.
Then parallely execute the following:
CREATE TABLE t1(id int) PARTITION BY RANGE(id);
CREATE TABLE part1 PARTITION OF t1 FOR VALUES FROM (0) TO (5);
CREATE TABLE part2 PARTITION OF t1 FOR VALUES FROM (5) TO (15)
PARTITION BY RANGE(id);
CREATE FOREIGN TABLE part2_1 PARTITION OF part2 FOR VALUES FROM (10)
TO (15) SERVER fdw

Now both the partitioned table having foreign table and a publication
will be created.

Regards,
Vignesh






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