Received: from eidolon.entheal.com (IDENT:root@cc13519-a.owml1.md.home.com [24.6.134.154]) by hub.org (8.9.3/8.9.3) with ESMTP id OAA33239; Mon, 25 Oct 1999 14:42:54 -0400 (EDT) (envelope-from jacob-christen@home.com) Received: from jchristen ([204.240.195.21]) by eidolon.entheal.com (8.9.3/8.9.3) with SMTP id OAA00904; Mon, 25 Oct 1999 14:45:27 -0400 Message-ID: <000a01bf1f18$8fa7fad0$4a0b030a@jchristen.educate.com> From: "Jacob Christen" To: , Subject: Re: [INTERFACES] Re: LIKE clause Date: Mon, 25 Oct 1999 14:13:46 -0400 MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 4.72.3110.5 X-MimeOLE: Produced By Microsoft MimeOLE V4.72.3110.3 -----Original Message----- From: Thomas Byrnes To: pgsql-interfaces@postgreSQL.org ; pgsql-general@postgreSQL.org Date: Monday, October 25, 1999 1:56 PM Subject: [INTERFACES] Re: LIKE clause >Alright, it seems simple enough, but I am having no luck figuring out the >syntax for the LIKE clause. > >I have tried: WHERE name LIKE 'A*' and other similar combinations to no >avail. Anyone have any suggestions? you're using the wrong wildcard character. try: SELECT name FROM my_table WHERE name LIKE 'A%'