Received: from postgresql.org.org (webmail.postgresql.org [216.126.85.28])
	by postgresql.org (8.11.3/8.11.1) with SMTP id f6NEEKf74470
	for <pgsql-interfaces@postgresql.org>;
	Mon, 23 Jul 2001 10:14:20 -0400 (EDT)
	(envelope-from pgsql-interfaces-owner@postgresql.org)
Received: from news.tht.net (news.hub.org [216.126.91.242])
	by postgresql.org (8.11.3/8.11.1) with ESMTP id f6KM1Ha37535
	for <pgsql-interfaces@postgresql.org>;
	Fri, 20 Jul 2001 18:01:17 -0400 (EDT)
	(envelope-from news@news.tht.net)
Received: (from news@localhost) by news.tht.net (8.11.4/8.11.4) id
 f6KLYot24005
	for pgsql-interfaces@postgresql.org;
	Fri, 20 Jul 2001 17:34:50 -0400 (EDT) (envelope-from news)
From: edp@enter.vg
X-Newsgroups: comp.databases.postgresql.interfaces
Subject: How to get id of newly inserted row with DBD?
Date: Fri, 20 Jul 2001 23:44:33 +0200
Organization: Hub.Org Networking Services (http://www.hub.org)
Lines: 11
Message-ID: <3B58A641.2AD5D1BF@enter.vg>
Mime-Version: 1.0
Content-Type: text/plain; charset=us-ascii
Content-Transfer-Encoding: 7bit
X-Complaints-To: scrappy@hub.org
X-Mailer: Mozilla 4.77 [en] (X11; U; Linux 2.4.5 i686)
X-Accept-Language: en
To: pgsql-interfaces@postgresql.org
X-Archive-Number: 200107/93
X-Sequence-Number: 1847

How to get id of newly inserted row with DBD?
I am using DBD-PG 1.01, DBI 1.18, Perl  5.6.1, Apache 1.3.20 and
mod_perl 1.25.

I need to show the usere the record it creates, but how do I know witch
row (rowid, oid) I should show?


L. G. Erlandsen