From: "Carl Shelbourne" <Carl.Shelbourne@marconi.com>
To: pgsql-interfaces@postgresql.org
Message-ID: <80256952.00549D8D.00@marconicomms.com>
Date: Wed, 6 Sep 2000 16:23:59 +0100
Subject: ISO8601 Time and ODBC
Mime-Version: 1.0
Content-type: text/plain; charset=us-ascii
Content-Disposition: inline


I am trying to get a fully qualified ISO8601 string

yyyy-mm-dd hh:mm:ss.h+MM:SS where MM:SS are the time offsets to GMT.

I am Using Postgres 7, UNIXodbc.

Using psql to query the table I get the time as:

2000-08-30 12:00:00+01

But the query via ODBC returns a SQL_C_TYPE_TIMESTAMP struct defined as

SQL_C_TYPE_TIMESTAMP  SQL_TIMESTAMP_STRUCT struct tagTIMESTAMP_STRUCT {
     SQLSMALLINT year;
     SQLUSMALLINT month;
     SQLUSMALLINT day;
     SQLUSMALLINT hour;
     SQLUSMALLINT minute;
     SQLUSMALLINT second;
     SQLUINTEGER fraction;
} TIMESTAMP_STRUCT;

The problem I have is I am working across timezones and I need to know the time
offset to GMT. Currently I am in the UK on BST +01:00, which psql seems to
return,

Does anybody know how I can get the offset to the time returned by Postgres
using ODBC??, this is not included in the above struct.

Thanks

Carl