Received: from mail.postgresql.org (webmail.postgresql.org [216.126.85.28]) by mail.postgresql.org (8.11.1/8.11.1) with SMTP id f26JnDx68622 for ; Tue, 6 Mar 2001 14:49:13 -0500 (EST) (envelope-from pgsql-interfaces-owner@postgresql.org) Received: from hotmail.com (oe57.law10.hotmail.com [64.4.14.192]) by mail.postgresql.org (8.11.1/8.11.1) with ESMTP id f261HTx77254 for ; Mon, 5 Mar 2001 20:17:29 -0500 (EST) (envelope-from balraju@hotmail.com) Received: from mail pickup service by hotmail.com with Microsoft SMTPSVC; Mon, 5 Mar 2001 17:17:25 -0800 X-Originating-IP: [65.5.68.124] Reply-To: "balraju" From: "balraju" To: Subject: problem with Inserting a new record in MS ACCESS through JDBC in JSP Date: Mon, 5 Mar 2001 17:23:04 -0800 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0007_01C0A598.EFFCAD60" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 5.50.4522.1200 X-MimeOLE: Produced By Microsoft MimeOLE V5.50.4522.1200 Message-ID: X-OriginalArrivalTime: 06 Mar 2001 01:17:25.0985 (UTC) FILETIME=[3446CD10:01C0A5DB] X-Archive-Number: 200103/59 X-Sequence-Number: 1220 This is a multi-part message in MIME format. ------=_NextPart_000_0007_01C0A598.EFFCAD60 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable I am getting problem with inserting records in MS Access database through J= DBC .=20 I am getting the error message as ' general error' I have tried using to insert the record through=20 stmt.execute(query) , stmt.executeUpdate() and with prepared statement bu= t getting the same message. Some one please help me get out of this problem. I would really appreciate if someone could send me the solution through ema= il . thanks balraju ------=_NextPart_000_0007_01C0A598.EFFCAD60 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable

I am getting problem with = inserting=20 records in MS Access database through JDBC .

I am getting the error mes= sage=20 as ' general error'

I have tried using to inse= rt the=20 record through

stmt.execute(query) = ,=20 stmt.executeUpdate() and with prepared statement but getting the same= =20 message.

Some one please help= me get out=20 of this problem.

I would really appreciate = if someone=20 could send me the solution through email .

thanks

balraju

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