Received: from localhost (unknown [200.46.204.182]) by postgresql.org (Postfix) with ESMTP id 13FF02E0103 for ; Sun, 2 Dec 2007 21:10:30 -0400 (AST) Received: from postgresql.org ([200.46.204.71]) by localhost (mx1.hub.org [200.46.204.182]) (amavisd-maia, port 10024) with ESMTP id 78883-09 for ; Sun, 2 Dec 2007 21:10:22 -0400 (AST) Received: from sss.pgh.pa.us (sss.pgh.pa.us [66.207.139.130]) by postgresql.org (Postfix) with ESMTP id 2B56B2E013B for ; Sun, 2 Dec 2007 21:10:27 -0400 (AST) Received: from sss2.sss.pgh.pa.us (tgl@localhost [127.0.0.1]) by sss.pgh.pa.us (8.14.1/8.14.1) with ESMTP id lB31APux000550; Sun, 2 Dec 2007 20:10:25 -0500 (EST) To: Michael Glaesemann cc: pgsql-performance@postgresql.org Subject: Re: EXPLAIN ANALYZE time calculations In-reply-to: References: <8C0EE80A-42A3-4CC1-850B-2A6B9220B422@seespotcode.net> <239.1196643379@sss.pgh.pa.us> Comments: In-reply-to Michael Glaesemann message dated "Sun, 02 Dec 2007 20:06:07 -0500" Date: Sun, 02 Dec 2007 20:10:25 -0500 Message-ID: <549.1196644225@sss.pgh.pa.us> From: Tom Lane X-Virus-Scanned: Maia Mailguard 1.0.1 X-Archive-Number: 200712/23 X-Sequence-Number: 27839 Michael Glaesemann writes: > I took startup time to be the time to return the first row *of the > first loop*. But it's actually the average startup time to return the > first row *in each loop*, right? Correct, just as the total time and tuples returned are averages over all the loops. regards, tom lane