From: "Fernando Hevia" <fhevia@ip-tel.com.ar>
To: "'Mike Diehl'" <jdiehl@sandia.gov>,
	"'SQL Postgresql List'" <pgsql-sql@postgresql.org>
Subject: Re: Problem with phone list.
Date: Wed, 15 Aug 2007 17:58:22 -0300
Organization: IP-TEL
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Try this:

Select *
from view v1
where duration =3D (select max(duration) from view v2 where =
v2.phone_number =3D
v1.phone_number)

You could get more than one call listed for the same number if many =
calls
match max(duration) for that number.


-----Mensaje original-----
De: pgsql-sql-owner@postgresql.org =
[mailto:pgsql-sql-owner@postgresql.org]
En nombre de Mike Diehl
Enviado el: Mi=E9rcoles, 15 de Agosto de 2007 17:28
Para: SQL Postgresql List
Asunto: [SQL] Problem with phone list.

Hi all.

I've qot a problem I need to solve.  I'm sure it's pretty simple; I just
can't=20
seem to get it, so here goes...

I've got a table, actually a view that joins 3 tables, that contains a =
phone

number, a unique id, and a call duration.

The phone number has duplicates in it but the unique id is unique.

I need to get a list of distinct phone numbers and the coorisponding =
largest

call duration.

I've got the idea that this should be a self-join on phone number where=20
a.id<>b.id, but I just can't seem to get the max duration.

Any hints would be much appreciated.

Mike.


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