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Re: selecting entire row on which one field is the minimum
2+ messages / 2 participants
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* selecting entire row on which one field is the minimum
@ 2003-05-21 01:16 edouard.boucher@free.fr
  2003-05-21 01:14 ` Re: selecting entire row on which one field is the minimum Rod Taylor <rbt@rbt.ca>
  0 siblings, 1 reply; 2+ messages in thread

From: edouard.boucher@free.fr @ 2003-05-21 01:16 UTC (permalink / raw)
  To: pgsql-sql

Hi,

i have a table with 2 fields, let's say A and B, both integers.
i would like to select all the A for which the B are minimum

i'm not sure i am clear, so here is an exemple :

A | B
1 | 5
2 | 2
3 | 3
4 | 2
5 | 2

in this situation, the query should return (2, 4, 5)
as it is very easy to ordre a table, i tought this query would be easy
too, but it is more difficult than it looks like.

thanks for help


Edouard Boucher



^ permalink  raw  reply  [nested|flat] 2+ messages in thread

* Re: selecting entire row on which one field is the minimum
  2003-05-21 01:16 selecting entire row on which one field is the minimum edouard.boucher@free.fr
@ 2003-05-21 01:14 ` Rod Taylor <rbt@rbt.ca>
  0 siblings, 0 replies; 2+ messages in thread

From: Rod Taylor @ 2003-05-21 01:14 UTC (permalink / raw)
  To: edouard.boucher@free.fr; +Cc: pgsql-sql

Something like this:

SELECT a FROM table WHERE B = (SELECT min(B) FROM table);


On Tue, 2003-05-20 at 21:16, edouard.boucher@free.fr wrote:
> Hi,
> 
> i have a table with 2 fields, let's say A and B, both integers.
> i would like to select all the A for which the B are minimum
> 
> i'm not sure i am clear, so here is an exemple :
> 
> A | B
> 1 | 5
> 2 | 2
> 3 | 3
> 4 | 2
> 5 | 2
> 
> in this situation, the query should return (2, 4, 5)
> as it is very easy to ordre a table, i tought this query would be easy
> too, but it is more difficult than it looks like.
> 
> thanks for help
> 
> 
> Edouard Boucher
> 
> ---------------------------(end of broadcast)---------------------------
> TIP 6: Have you searched our list archives?
> 
> http://archives.postgresql.org
-- 
Rod Taylor <rbt@rbt.ca>

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