X-Original-To: pgsql-sql-postgresql.org@localhost.postgresql.org Received: from localhost (unknown [64.117.224.130]) by svr1.postgresql.org (Postfix) with ESMTP id 3AC4BD1BAF0 for ; Fri, 22 Aug 2003 03:26:55 -0300 (ADT) Received: from svr1.postgresql.org ([64.117.224.193]) by localhost (neptune.hub.org [64.117.224.130]) (amavisd-new, port 10024) with ESMTP id 13167-02 for ; Fri, 22 Aug 2003 03:26:25 -0300 (ADT) Received: from mailout02.sul.t-online.com (mailout02.sul.t-online.com [194.25.134.17]) by svr1.postgresql.org (Postfix) with ESMTP id C402FD1BAD6 for ; Fri, 22 Aug 2003 03:26:23 -0300 (ADT) Received: from umsgate01.aul.t-online.de by mailout02.sul.t-online.com with smtp id 19q5NQ-0005mq-01; Fri, 22 Aug 2003 08:26:24 +0200 Received: from webmail.t-online.de (JT36t4ZaQeJkUDpz6vQ2dZToBLUDAsDqLaLmrC-X6VnJ16wRDzDggE@[172.18.16.209]) by umsgate01.bbul.t-online.de with smtp id 19q5NJ-1GA0tU0; Fri, 22 Aug 2003 08:26:17 +0200 To: pgsql-sql@postgresql.org Subject: date calculation From: MichaelHoeller@t-online.de Date: Fri, 22 Aug 2003 08:25:51 +0200 (CEST) Message-ID: <1061533501.3f45b73d6566d@webmail.t-online.de> X-Approved: 5ba5d48049593ecb2L81K-Wq0uu5gj1hcn7kXkqkCCSf2qon X-Mailer: T-Online WebMail 3.10 X-Complaints-To: abuse#webmail@t-online.com X-Seen: false X-ID: JT36t4ZaQeJkUDpz6vQ2dZToBLUDAsDqLaLmrC-X6VnJ16wRDzDggE@t-dialin.net X-Virus-Scanned: by amavisd-new at postgresql.org X-Archive-Number: 200308/265 X-Sequence-Number: 14881 Hi there, I have a problem calculating a date. A field carries the date as passed seconds since Jan 1st 1970. How can I get the date as dd.mm.yyyy out of this?? Thanks a lot Michael