Subject: Re: Simple Question
From: Guy Fraser <guy@incentre.net>
Reply-To: guy@incentre.net
To: Terry Lee Tucker <terry@esc1.com>
Cc: pgsql-sql@postgresql.org
In-Reply-To: <200501111642.21716.terry@esc1.com>
References: <200501111642.21716.terry@esc1.com>
Content-Type: text/plain
Organization: The Internet Centre
Date: Tue, 11 Jan 2005 15:06:34 -0700
Message-Id: <1105481194.5382.18.camel@sigurd.incentre.net>
Mime-Version: 1.0
Content-Transfer-Encoding: 7bit

Convert to seconds first (3600 sec/hr) :

select (
 '3600'::int4 
 * '478'::int4 
 / '45.0'::float8
)::int4::reltime::interval ;
 interval
----------
 10:37:20
(1 row)

I don't know if "::int4::reltime::interval" is the best 
way to end up with an interval, but its the only way I 
could figure out how to do it off the top of my head.

On Tue, 2005-11-01 at 16:42 -0500, Terry Lee Tucker wrote:
> Hello:
> 
> I'm trying to figure out how to convert a floating point value into an 
> interval of time. I'm calculating the time required to drive from point A to 
> point B. For the sake of this question, we'll just say it is miles/speed. So:
> 
> drv_time = 478 / 45.0;
> 
> The value of this is: 10.6222222222222222
> 
> Is there a way of converting this value to an interval. It seems that INTERVAL 
> only works with a quoted literal value.
> 
> If I type:
> rnd=# select interval '10.8444444444444444 hours';
>           interval
> ----------------------------
>  @ 10 hours 50 mins 40 secs
> (1 row)
> 
> Anybody have an pointers?
> 
> Thanks...
> 
> 
>  Work: 1-336-372-6812
>  Cell: 1-336-363-4719
> email: terry@esc1.com
> 
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> 
-- 
Guy Fraser
Network Administrator
The Internet Centre
1-888-450-6787
(780)450-6787