Subject: Re: generate_series with left join
From: "Pedro B." <pedro.borracha@msglab.com>
To: Aaron Bono <postgresql@aranya.com>
Cc: pgsql-sql@postgresql.org
In-Reply-To: <bf05e51c0606281316n4a90cd50m51fa89922a878856@mail.gmail.com>
References: <1151510424.28638.18.camel@m3ta.msglab.mine.nu>
	<bf05e51c0606281134s57ad9b37nd1991ad7c8928dd6@mail.gmail.com>
	<1151522786.2238.46.camel@localhost.localdomain>
	<bf05e51c0606281310l5db30741g97678d71c837266d@mail.gmail.com>
	<bf05e51c0606281316n4a90cd50m51fa89922a878856@mail.gmail.com>
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Date: Wed, 28 Jun 2006 21:28:30 +0100
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On Wed, 2006-06-28 at 15:16 -0500, Aaron Bono wrote:
> This should work too:
> 
> select
>     year_list.year,
>     one_list.one_count,
>     two_list.two_count
> FROM (
>     select years
>     from generate_series(2006,2009) as years
> ) year_list
> left outer join ( 
>     select
>         date_part('year', one.date) as one_year,
>         count(one.*) as one_count
>     from mytable as one
>     where one.cause = 1
>     group by
>         date_part('year', one.date)
> ) one_list on (year_list.years = one_year) 
> left outer join (
>     select
>         date_part('year', two.date) as two_year,
>         count(two.*) as two_count
>     from mytable as two
>     where two.cause = 2
>     group by
>         date_part('year', two.date)
> ) two_list on (year_list.years = two_year)
> ;


Aaron, 

I confess i will take some time to digest the amazing code you just
sent, but in the meantime, let me tell you right away that both work
just as i needed.

I will stop pulling my hairs now.
Thank you so much. 

\\pb


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