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In-Reply-To: <C78DBD69.918D%tsakai@gallo.ucsf.edu>
References: <C78DBD69.918D%tsakai@gallo.ucsf.edu>
Date: Tue, 2 Feb 2010 21:38:42 +0100
Message-ID: <162867791002021238j31ad8d7cge44bbce28ff451f3@mail.gmail.com>
Subject: Re: please help me on regular expression
From: Pavel Stehule <pavel.stehule@gmail.com>
To: Tena Sakai <tsakai@gallo.ucsf.edu>
Cc: "pgsql-sql@postgresql.org" <pgsql-sql@postgresql.org>
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2010/2/2 Tena Sakai <tsakai@gallo.ucsf.edu>:
> Hi everybody,
>
> I need a bit of help on postgres reqular expression.
> With a table of the following definition:
>
> =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 Table "tsakai.pheno"
> =C2=A0Column =C2=A0 | =C2=A0 =C2=A0 =C2=A0 Type =C2=A0 =C2=A0 =C2=A0 =C2=
=A0| Modifiers
> -----------+-------------------+-----------
> =C2=A0subjectid | integer =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 | not null
> =C2=A0height =C2=A0 =C2=A0| character varying | not null
> =C2=A0race =C2=A0 =C2=A0 =C2=A0| character varying | not null
> =C2=A0blood =C2=A0 =C2=A0 | character varying | not null
>
> I want to catch entries in height column that includes a
> decimal point. =C2=A0Here's my attempt:
>
> =C2=A0select subjectid, height
> =C2=A0 from tsakai.pheno
> =C2=A0where height ~ '[:digit:]+.[:digit:]+';
>
> Which returns 0 rows, but if I get rid of where clause,
> I get rows like:
>
> =C2=A0subjectid | height
> -----------+--------
> =C2=A0 =C2=A0 55379 | 70.5
> =C2=A0 =C2=A0 55383 | 69
> =C2=A0 =C2=A0 55395 | 70
> =C2=A0 =C2=A0 56173 | 71
> =C2=A0 =C2=A0 56177 | 65.5
> =C2=A0 =C2=A0 56178 | 70
> =C2=A0 =C2=A0 =C2=A0 . =C2=A0 =C2=A0 =C2=A0.
> =C2=A0 =C2=A0 =C2=A0 . =C2=A0 =C2=A0 =C2=A0.
>
> And when I escape that dot after first plus sign with a backslash,
> like this:
> =C2=A0where height ~ '[:digit:]+\.[:digit:]+';
> then I get complaint:
>
> WARNING: =C2=A0nonstandard use of escape in a string literal
> LINE 3: where height ~ '[:digit:]+\.[:digit:]+';
> =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=
=A0 ^
> HINT: =C2=A0Use the escape string syntax for escapes, e.g., E'\r\n'.
>
> From there, it was a downward spiral descent...
>

you have to use a prefix 'E' - E'some string with \backslash'

for your case the reg. expr could be

postgres=3D# select '70.5' ~ e'\\d+\.\\d+';
 ?column?
----------
 t
(1 row)

http://www.postgresql.org/docs/8.1/static/functions-matching.html

or

postgres=3D# select '70.5' ~ e'[[:digit:]]+\.[[:digit:]]+';
 ?column?
----------
 t
(1 row)

Regards
Pavel Stehule
> Please help.
>
> Thank you.
>
> Regards,
>
> Tena Sakai
> tsakai@gallo.ucsf.edu
>
>
>
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