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To: Gregory Stark <stark@enterprisedb.com>
cc: "Michele Petrazzo - Unipex srl" <michele.petrazzo@unipex.it>,
	"Pgsql-Sql" <pgsql-sql@postgresql.org>
Subject: Re: functions are returns columns 
In-reply-to: <878x55dhau.fsf@oxford.xeocode.com> 
References: <4734B921.5050704@unipex.it>
	<162867790711091235i7e77abcch27731d91285949b6@mail.gmail.com>
	<4735EC6F.5050908@unipex.it> <878x55dhau.fsf@oxford.xeocode.com>
Comments: In-reply-to Gregory Stark <stark@enterprisedb.com>
	message dated "Sat, 10 Nov 2007 19:36:09 +0000"
Date: Sat, 10 Nov 2007 14:46:35 -0500
Message-ID: <19335.1194723995@sss.pgh.pa.us>
From: Tom Lane <tgl@sss.pgh.pa.us>
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Gregory Stark <stark@enterprisedb.com> writes:
> You're almost there:

> CREATE FUNCTION getfoo (IN int, OUT int, OUT int) returns setof record(int,int) AS $$
>   SELECT fooid, foosubid FROM foo WHERE fooid = $1;
> $$ LANGUAGE SQL;

Not quite --- it's just "returns setof record".  The output column types
are defined by the OUT parameters.  The only reason you need the returns
clause is to have a place to stick the "setof" specification ...

			regards, tom lane