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* alias problem on join
@ 2004-02-06 11:38 Gary Stainburn <gary.stainburn@ringways.co.uk>
2004-02-06 11:46 ` Re: alias problem on join Tomasz Myrta <jasiek@klaster.net>
0 siblings, 1 reply; 2+ messages in thread
From: Gary Stainburn @ 2004-02-06 11:38 UTC (permalink / raw)
To: pgsql-sql
Hi folks,
I've got an accounts table and a transactions table and want to do a summary
join. If I do:
bank=# select aid, aname, aodraft from accounts a
bank-# left outer join (select account, sum(amount) as balance
bank(# from statement group by account) as s
bank-# on s.account = a.aid;
I get the results I want, but I need to rename the aid column to 'key' so that
I can feed it into a standard routine I have in PHP to build a hash. If I
do:
bank=# select aid as key, aname, aodraft from accounts a
bank-# left outer join (select account, sum(amount) as balance
bank(# from statement group by account) as s
bank-# on s.account = a.key;
I get
ERROR: No such attribute or function 'key'
Any ideas why?
Also, I'm sure I can do this more efficiently as a single select/join, but
can't seem to work out why (Friday morning syndrome). Anyone give me a clue?
--
Gary Stainburn
This email does not contain private or confidential material as it
may be snooped on by interested government parties for unknown
and undisclosed purposes - Regulation of Investigatory Powers Act, 2000
^ permalink raw reply [nested|flat] 2+ messages in thread
* Re: alias problem on join
2004-02-06 11:38 alias problem on join Gary Stainburn <gary.stainburn@ringways.co.uk>
@ 2004-02-06 11:46 ` Tomasz Myrta <jasiek@klaster.net>
0 siblings, 0 replies; 2+ messages in thread
From: Tomasz Myrta @ 2004-02-06 11:46 UTC (permalink / raw)
To: Gary Stainburn <gary.stainburn@ringways.co.uk>; +Cc: pgsql-sql
Dnia 2004-02-06 12:38, Użytkownik Gary Stainburn napisał:
> Hi folks,
>
> I've got an accounts table and a transactions table and want to do a summary
> join. If I do:
>
> bank=# select aid, aname, aodraft from accounts a
> bank-# left outer join (select account, sum(amount) as balance
> bank(# from statement group by account) as s
> bank-# on s.account = a.aid;
>
> I get the results I want, but I need to rename the aid column to 'key' so that
> I can feed it into a standard routine I have in PHP to build a hash. If I
> do:
>
> bank=# select aid as key, aname, aodraft from accounts a
> bank-# left outer join (select account, sum(amount) as balance
> bank(# from statement group by account) as s
> bank-# on s.account = a.key;
This is an output column alias and it can't be used in where clause.
In where clause you have to use original column name and the only
aliases you can use there are table aliases.
Regards,
Tomasz Myrta
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2004-02-06 11:38 alias problem on join Gary Stainburn <gary.stainburn@ringways.co.uk>
2004-02-06 11:46 ` Tomasz Myrta <jasiek@klaster.net>
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