X-Original-To: pgsql-sql-postgresql.org@localhost.postgresql.org Received: from localhost (unknown [200.46.204.144]) by svr1.postgresql.org (Postfix) with ESMTP id 8ABBE3A52A4 for ; Sun, 9 Jan 2005 18:32:22 +0000 (GMT) Received: from svr1.postgresql.org ([200.46.204.71]) by localhost (av.hub.org [200.46.204.144]) (amavisd-new, port 10024) with ESMTP id 72156-01 for ; Sun, 9 Jan 2005 18:32:15 +0000 (GMT) Received: from ganymede.hub.org (blk-224-134-163.eastlink.ca [24.224.134.163]) by svr1.postgresql.org (Postfix) with ESMTP id 4DED43A503F for ; Sun, 9 Jan 2005 18:32:15 +0000 (GMT) Received: by ganymede.hub.org (Postfix, from userid 1000) id 6BEA15EF2B; Sun, 9 Jan 2005 14:32:15 -0400 (AST) Received: from localhost (localhost [127.0.0.1]) by ganymede.hub.org (Postfix) with ESMTP id 6306E5E141 for ; Sun, 9 Jan 2005 14:32:15 -0400 (AST) Date: Sun, 9 Jan 2005 14:32:15 -0400 (AST) From: "Marc G. Fournier" X-X-Sender: scrappy@ganymede.hub.org To: pgsql-sql@postgresql.org Subject: Easier way to 'strip' on multiple matches? Message-ID: <20050109143121.G6902@ganymede.hub.org> MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII; format=flowed X-Virus-Scanned: by amavisd-new at hub.org X-Spam-Status: No, hits=0.946 tagged_above=0 required=5 tests=AWL, FORGED_RCVD_HELO, RCVD_IN_NJABL_DUL, RCVD_IN_SORBS_DUL X-Spam-Level: X-Archive-Number: 200501/30 X-Sequence-Number: 19818 I need to strip out all spaces, and all \' from a string ... is there an easier way then doing: select lower(replace(replace(name, ' ', ''), '\\\'', '')) from business; Thanks ... ---- Marc G. Fournier Hub.Org Networking Services (http://www.hub.org) Email: scrappy@hub.org Yahoo!: yscrappy ICQ: 7615664