From: Terry Lee Tucker <terry@esc1.com>
Organization: Enhanced Solutions Computing
To: pgsql-sql@postgresql.org
Subject: Re: Simple Question
Date: Tue, 11 Jan 2005 17:21:25 -0500
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Thanks for the reply. My answer was a little different than yours because I 
used 488 instead of 478. Well, that three ways so far ;o)

On Tuesday 11 January 2005 05:06 pm, Guy Fraser saith:
> Convert to seconds first (3600 sec/hr) :
>
> select (
>  '3600'::int4
>  * '478'::int4
>  / '45.0'::float8
> )::int4::reltime::interval ;
>  interval
> ----------
>  10:37:20
> (1 row)
>
> I don't know if "::int4::reltime::interval" is the best
> way to end up with an interval, but its the only way I
> could figure out how to do it off the top of my head.
>
> On Tue, 2005-11-01 at 16:42 -0500, Terry Lee Tucker wrote:
> > Hello:
> >
> > I'm trying to figure out how to convert a floating point value into an
> > interval of time. I'm calculating the time required to drive from point A
> > to point B. For the sake of this question, we'll just say it is
> > miles/speed. So:
> >
> > drv_time = 478 / 45.0;
> >
> > The value of this is: 10.6222222222222222
> >
> > Is there a way of converting this value to an interval. It seems that
> > INTERVAL only works with a quoted literal value.
> >
> > If I type:
> > rnd=# select interval '10.8444444444444444 hours';
> >           interval
> > ----------------------------
> >  @ 10 hours 50 mins 40 secs
> > (1 row)
> >
> > Anybody have an pointers?
> >
> > Thanks...
> >
> >
> >  Work: 1-336-372-6812
> >  Cell: 1-336-363-4719
> > email: terry@esc1.com
> >
> > ---------------------------(end of broadcast)---------------------------
> > TIP 4: Don't 'kill -9' the postmaster
>
> --
> Guy Fraser
> Network Administrator
> The Internet Centre
> 1-888-450-6787
> (780)450-6787
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 8: explain analyze is your friend

 Work: 1-336-372-6812
 Cell: 1-336-363-4719
email: terry@esc1.com