X-Original-To: pgsql-sql-postgresql.org@localhost.postgresql.org Received: from localhost (av.hub.org [200.46.204.144]) by postgresql.org (Postfix) with ESMTP id 89A749DC839 for ; Tue, 3 Jan 2006 22:42:51 -0400 (AST) Received: from postgresql.org ([200.46.204.71]) by localhost (av.hub.org [200.46.204.144]) (amavisd-new, port 10024) with ESMTP id 00863-03 for ; Tue, 3 Jan 2006 22:42:55 -0400 (AST) X-Greylist: from auto-whitelisted by SQLgrey- Received: from tigger.fuhr.org (tigger.fuhr.org [63.214.45.158]) by postgresql.org (Postfix) with ESMTP id 3E39A9DC824 for ; Tue, 3 Jan 2006 22:42:49 -0400 (AST) Received: from winnie.fuhr.org (winnie.fuhr.org [10.1.0.1]) by tigger.fuhr.org (8.13.3/8.13.3) with ESMTP id k042gl7e015735 (version=TLSv1/SSLv3 cipher=DHE-RSA-AES256-SHA bits=256 verify=OK); Tue, 3 Jan 2006 19:42:50 -0700 (MST) (envelope-from mfuhr@winnie.fuhr.org) Received: from winnie.fuhr.org (localhost [127.0.0.1]) by winnie.fuhr.org (8.13.4/8.13.4) with ESMTP id k042gl6o011043; Tue, 3 Jan 2006 19:42:47 -0700 (MST) (envelope-from mfuhr@winnie.fuhr.org) Received: (from mfuhr@localhost) by winnie.fuhr.org (8.13.4/8.13.4/Submit) id k042gluH011042; Tue, 3 Jan 2006 19:42:47 -0700 (MST) (envelope-from mfuhr) Date: Tue, 3 Jan 2006 19:42:47 -0700 From: Michael Fuhr To: Dan Tenenbaum Cc: pgsql-sql@postgresql.org Subject: Re: getting a query column to return 0 if nothing matches Message-ID: <20060104024246.GA10993@winnie.fuhr.org> References: <65029d820601031415w34794135v307ef13b37d5cd10@mail.gmail.com> Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline In-Reply-To: <65029d820601031415w34794135v307ef13b37d5cd10@mail.gmail.com> X-Virus-Scanned: by amavisd-new at hub.org X-Spam-Status: No, score=0.07 required=5 tests=[AWL=0.070] X-Spam-Score: 0.07 X-Spam-Level: X-Archive-Number: 200601/12 X-Sequence-Number: 23801 On Tue, Jan 03, 2006 at 02:15:25PM -0800, Dan Tenenbaum wrote: > I want to show all rows where the first part of the WHERE clause is true, > regardless of whether the provider_key is in the login_provider table (in > that cause, I want to show 0 in that column). Sounds like you're looking for an outer join. http://www.postgresql.org/docs/8.1/interactive/tutorial-join.html http://www.postgresql.org/docs/8.1/interactive/queries-table-expressions.html -- Michael Fuhr