Received: from localhost (maia-4.hub.org [200.46.204.183]) by postgresql.org (Postfix) with ESMTP id 67D889FB2DF for ; Tue, 6 Feb 2007 02:41:45 -0400 (AST) Received: from postgresql.org ([200.46.204.71]) by localhost (mx1.hub.org [200.46.204.183]) (amavisd-new, port 10024) with ESMTP id 11686-01 for ; Tue, 6 Feb 2007 02:41:43 -0400 (AST) X-Greylist: from auto-whitelisted by SQLgrey-1.7.4 Received: from moutng.kundenserver.de (moutng.kundenserver.de [212.227.126.188]) by postgresql.org (Postfix) with ESMTP id 4A6969FB282 for ; Tue, 6 Feb 2007 02:41:42 -0400 (AST) Received: from [194.25.154.138] (helo=webserv.wug.de) by mrelayeu.kundenserver.de (node=mrelayeu4) with ESMTP (Nemesis), id 0ML21M-1HEK1N1Ewp-0002KT; Tue, 06 Feb 2007 07:41:41 +0100 Received: from kretschmer by webserv.wug.de with local (Exim 3.36 #1) id 1HEK1M-0001yE-00 for pgsql-sql@postgresql.org; Tue, 06 Feb 2007 07:41:40 +0100 Date: Tue, 6 Feb 2007 07:41:40 +0100 From: "A. Kretschmer" To: pgsql-sql@postgresql.org Subject: Re: sql Message-ID: <20070206064140.GA6761@a-kretschmer.de> References: Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline In-Reply-To: X-OS: Debian/GNU Linux - weil ich es mir Wert bin! X-Message-Flag: "Windows" is not the answer. "Windows" is the question and the answer is "no"! User-Agent: Mutt/1.5.9i X-Provags-ID: kundenserver.de abuse@kundenserver.de login:51ea9561fc3f6d9539a2acd743e4748c X-Provags-ID2: V01U2FsdGVkX185OjGhJHLCe+GhCqiEfxykgxoG2p6cJtzKnsI08pEkja/A/rGLvsYcDlXF5YURUls0stFCoofC8qKmFwuYz4hX2Q14sN3n9LG64YgMY1iwP6YLq1h9hEe0 X-Virus-Scanned: Maia Mailguard 1.0.1 X-Archive-Number: 200702/45 X-Sequence-Number: 27379 am Fri, dem 02.02.2007, um 13:09:09 +0530 mailte Shyju Narayanan folgendes: > Hi All > > > BUT I NEED THE RESULT AS > entry_user_id_int COUNT(VC) COUNT(VE) COUNT(CV) COUNT(SC) TOTAL > 78 1 1 8 1 11 > You need something like this (i called the table foo and without the sc-column): select entry_user_id_int, sum(case when category_id_chv = 'VC' then 1 else 0 end) as "count(vc)", sum(case when category_id_chv = 'VE' then 1 else 0 end), sum(case when category_id_chv = 'CV' then 1 else 0 end), sum(1) from foo where entry_user_id_int = 78 group by entry_user_id_int; entry_user_id_int | count(vc) | sum | sum | sum -------------------+-----------+-----+-----+----- 78 | 1 | 1 | 8 | 11 Andreas -- Andreas Kretschmer Kontakt: Heynitz: 035242/47150, D1: 0160/7141639 (mehr: -> Header) GnuPG-ID: 0x3FFF606C, privat 0x7F4584DA http://wwwkeys.de.pgp.net