Message-Id: <200705142316.l4ENGGS4010065@contactbda.com>
From: "Jim Buttafuoco" <jim@contactbda.com>
To: "'Bryce Nesbitt'" <bryce1@obviously.com>,
	<pgsql-sql@postgresql.org>
Subject: Re: Doing a conditional aggregate (e.g. count(*) if x=y) in postgres?
Date: Mon, 14 May 2007 19:16:14 -0400
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In-Reply-To: <4648E8F1.4020609@obviously.com>
thread-index: AceWe0z6uOhLGWFbR+uOiaw4T6F+tQAAlgWw

Use case statement and sum to get a count where status=20...

For example

Select sum(case when status=20 then 1 else 0 end) as status20,
       Sum(case when status=30 then 1 else 0 end) as status30
....


-----Original Message-----
From: pgsql-sql-owner@postgresql.org [mailto:pgsql-sql-owner@postgresql.org]
On Behalf Of Bryce Nesbitt
Sent: Monday, May 14, 2007 6:56 PM
To: pgsql-sql@postgresql.org
Subject: [SQL] Doing a conditional aggregate (e.g. count(*) if x=y) in
postgres?

All;
Is there a way to get a conditional aggregate?  I have this two column view:

 SELECT count(*) AS count, xx_plan.plan_name
   FROM xx_membership
   JOIN xx_account USING (account_id)
   JOIN xx_plan USING (plan_id)
  WHERE xx_membership.status = 10
  GROUP BY xx_plan.plan_name;

And would like to add additional columns (not rows) breaking out
"status=20" and "status=30" totals.
Is this possible without a stored procedure?


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