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complex join question
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* complex join question
@ 2010-02-12 22:32 Louis-David Mitterrand <vindex+lists-pgsql-sql@apartia.org>
  2010-02-12 23:55 ` Re: complex join question Tim Landscheidt <tim@tim-landscheidt.de>
  0 siblings, 1 reply; 2+ messages in thread

From: Louis-David Mitterrand @ 2010-02-12 22:32 UTC (permalink / raw)
  To: pgsql-sql

Hi,

Here is my schema:

cruise_line -> ship(id_line) -> cruise_type(id_ship) -> cruise(id_cruise_type) 
	-> price(id_cruise, id_currency) <- currency (USD,GBP,EUR,CAD)

(a 'cruise' is a 'cruise_type' + a date)

I am trying to display a count of cruise's for each ship and each
currency even if that count is 0.

But I am having trouble building the query, as some 'cruise's might not
(yet) have a 'price' in all currencies and so no link to 'currency'.

Thanks,



^ permalink  raw  reply  [nested|flat] 2+ messages in thread

* Re: complex join question
  2010-02-12 22:32 complex join question Louis-David Mitterrand <vindex+lists-pgsql-sql@apartia.org>
@ 2010-02-12 23:55 ` Tim Landscheidt <tim@tim-landscheidt.de>
  0 siblings, 0 replies; 2+ messages in thread

From: Tim Landscheidt @ 2010-02-12 23:55 UTC (permalink / raw)
  To: pgsql-sql

Louis-David Mitterrand <vindex+lists-pgsql-sql@apartia.org> wrote:

> Here is my schema:

> cruise_line -> ship(id_line) -> cruise_type(id_ship) -> cruise(id_cruise_type)
> 	-> price(id_cruise, id_currency) <- currency (USD,GBP,EUR,CAD)

> (a 'cruise' is a 'cruise_type' + a date)

> I am trying to display a count of cruise's for each ship and each
> currency even if that count is 0.

> But I am having trouble building the query, as some 'cruise's might not
> (yet) have a 'price' in all currencies and so no link to 'currency'.

You're probably looking for a "LEFT JOIN".

Tim




^ permalink  raw  reply  [nested|flat] 2+ messages in thread


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2010-02-12 22:32 complex join question Louis-David Mitterrand <vindex+lists-pgsql-sql@apartia.org>
2010-02-12 23:55 ` Tim Landscheidt <tim@tim-landscheidt.de>

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