From: Leif Biberg Kristensen <leif@solumslekt.org>
To: pgsql-sql@postgresql.org
Subject: Re: replace " with nothing
Date: Wed, 11 May 2011 23:11:07 +0200
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On Wednesday 11 May 2011 22:29:40 Tony Capobianco wrote:
> We are converting from Oracle to Postgres.  An Oracle script contains
> this line:
>=20
>  select replace(firstname,'"'), memberid, emailaddress from members;
>=20
> in an effort to replace the " with nothing.  How can I achieve the same
> result with Postgres?
>=20
> Here's the Postgres error I get:
>=20
> select replace(firstname,'"'), memberid, emailaddress from members;
> ERROR:  function replace(character varying, unknown) does not exist
> LINE 1: select replace(firstname,'"'), memberid, emailaddress from m...

=46rom the fine documentation=20
<http://www.postgresql.org/docs/current/static/functions-string.html>

replace(string text, from text, to text)

Example: replace('abcdefabcdef', 'cd', 'XX')

IOW, this function takes three parameters, the first one being the actual t=
ext=20
you want to make a replace on. Yor ecample above shoul probably be written =
as:

SELECT REPLACE((SELECT firstname FROM members), '%', ''), memberid,=20
emailaddress FROM members;

although it's a little above me why you would want to select firstname in t=
he=20
first place when you proceed to replace it with nothing.

regards, Leif