X-Original-To: pgsql-sql-postgresql.org@localhost.postgresql.org Received: from localhost (unknown [200.46.204.2]) by svr1.postgresql.org (Postfix) with ESMTP id 5CF2BD1E94D for ; Wed, 14 Apr 2004 00:30:53 -0300 (ADT) Received: from svr1.postgresql.org ([200.46.204.71]) by localhost (neptune.hub.org [200.46.204.2]) (amavisd-new, port 10024) with ESMTP id 14782-05 for ; Wed, 14 Apr 2004 00:30:52 -0300 (ADT) Received: from sss.pgh.pa.us (sss.pgh.pa.us [66.207.139.130]) by svr1.postgresql.org (Postfix) with ESMTP id 819D2D1E944 for ; Wed, 14 Apr 2004 00:30:51 -0300 (ADT) Received: from sss2.sss.pgh.pa.us (tgl@localhost [127.0.0.1]) by sss.pgh.pa.us (8.12.11/8.12.11) with ESMTP id i3E3Ul88029773; Tue, 13 Apr 2004 23:30:47 -0400 (EDT) To: "Dennis" Cc: "postgres SQL" Subject: Re: function returning array In-reply-to: References: Comments: In-reply-to "Dennis" message dated "Tue, 13 Apr 2004 18:41:52 -0400" Date: Tue, 13 Apr 2004 23:30:47 -0400 Message-ID: <29772.1081913447@sss.pgh.pa.us> From: Tom Lane X-Virus-Scanned: by amavisd-new at postgresql.org X-Archive-Number: 200404/124 X-Sequence-Number: 17499 "Dennis" writes: > I am trying to return an array from a function and don't seem to be having > luck. Seems to work for me ... what PG version are you using? regression=# create function parseString() returns varchar[] as regression-# 'begin return \'{abc,def,ghi}\'; end' language plpgsql; CREATE FUNCTION regression=# select parseString(); parsestring --------------- {abc,def,ghi} (1 row) regression=# create function foo() returns varchar as ' regression'# declare regression'# results varchar[]; regression'# tmpv varchar; regression'# begin regression'# results := parseString(); regression'# tmpv := results[1]; regression'# RAISE NOTICE '' tmpv = % '',tmpv; regression'# return tmpv; regression'# end' language plpgsql; CREATE FUNCTION regression=# select foo(); NOTICE: tmpv = abc foo ----- abc (1 row) regards, tom lane