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In-Reply-To: <E8B4F516-1647-4621-B744-5DB66E1EC682@eclinic.com.au>
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	<E8B4F516-1647-4621-B744-5DB66E1EC682@eclinic.com.au>
Date: Tue, 16 Jun 2009 15:45:03 -0700
Message-ID: <396486430906161545u512acc33lbd67f78174434509@mail.gmail.com>
Subject: Re: left outer join on more than 2 tables?
From: Richard Broersma <richard.broersma@gmail.com>
To: Gavin Baumanis <gavinb@eclinic.com.au>
Cc: Carol Cheung <cacheung@consumercontact.com>, pgsql-sql@postgresql.org
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On Tue, Jun 16, 2009 at 2:39 PM, Gavin Baumanis<gavinb@eclinic.com.au> wrot=
e:
> At the risk of being wrong.... (I'm always ready to learn something new) =
-
> and seemingly I'm only too happy to be wrong!...
>
> And... it might even be that it is exactly the same result - but I would
> have proposed;
>
> SELECT
> =A0 =A0R.region_name,
> =A0 =A0Count(*) AS RegionComplaints
> FROM
> =A0 =A0Region AS R
> =A0 =A0 =A0 =A0LEFT JOIN City AS Ci
> =A0 =A0 =A0 =A0 =A0 =A0LEFT JOIN Complaint AS Cm ON Ci.id =3D Cm.city_id
> =A0 =A0 =A0ON R.id =3D C.region_id
> GROUP BY
> =A0 =A0R.region_name;

Yup, it produces the same result.


--=20
Regards,
Richard Broersma Jr.

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