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From: "Nicolas Fertig" <nfertig@swissnow.ch>
X-Newsgroups: comp.databases.postgresql.sql
Subject: OUTER JOIN with filter
Date: Sat, 1 Mar 2003 19:53:27 +0100
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Hello,

Can anyone help me with the problem bellow ?

I want to have all the row in table "table_main" with the value in the table
"table_slave" (value or null if not exist)

It is possible to have the same result without sub-select in OUTER JOIN
(speed problem on big table) ?

Actualy this is what I make...

CREATE TABLE "table_main" (
   "id" int4,
   "some_field" varchar(100)
);

CREATE TABLE "table_slave" (
   "id" int4,
   "name" varchar(100),
   "c1" varchar(30)
);

SELECT TM.some_field, TS.name
FROM table_main TM
LEFT OUTER JOIN (SELECT name FROM table_slave WHERE c1 = 'myvalue') TS
USING(id)


the request bellow is not correct:

SELECT TM.some_filed, TS.name
FROM table_main TM
LEFT OUTER JOIN table_slave TS USING(id)
WHERE (TS.c1 = 'myc1' OR TS.c1 IS NULL)

Many thanks,

Nicolas