Message-ID: <437D1C75.4080409@PresiNET.com>
Date: Thu, 17 Nov 2005 16:12:37 -0800
From: Bricklen Anderson <BAnderson@PresiNET.com>
User-Agent: Debian Thunderbird 1.0.7 (X11/20051017)
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To: Dawn Buie <dawn@squeegeemedia.com>
CC: pgsql-sql@postgresql.org
Subject: Re: how to do a find and replace
References: <1132269492.30942.20.camel@dev11dt.corp.localmatters.com>
	<5d001d303f001ea0847254c3f0a352d9@squeegeemedia.com>
	<437D1862.2060402@PresiNET.com>
	<be1d8fb1d0b1bb5cf79b8e73b66b5609@squeegeemedia.com>
In-Reply-To: <be1d8fb1d0b1bb5cf79b8e73b66b5609@squeegeemedia.com>
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Dawn Buie wrote:
> I used:
> 
> update media_instance set location=replace(location,'v.','')
> where location like '%/0/v.%'
> 
> and that did work-
> 
> thank you very much.
> 
> it seems to me that the replace function is the same as translate()- no?
> 
Right, I forgot your WHERE clause.

Some more details on those functions can be found here:
http://www.postgresql.org/docs/8.1/interactive/functions-string.html#FUNCTIONS-STRING-OTHER

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