Message-ID: <4741F63A.6070500@planit.com.br>
Date: Mon, 19 Nov 2007 18:46:50 -0200
From: "Luiz K. Matsumura" <luiz@planit.com.br>
Organization: Plan IT Tecnologia =?ISO-8859-1?Q?Inform=E1tica_Ltda=2E?=
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To: pgsql-sql@postgresql.org
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Subject: Aggregate question (Sum)

Hi All,

I want to know if there are an easy manner to do an SQL like this bellow
where TotalOrdersValue sum the order.total just one time per order (as 
count(DISTINCT order.id) do)

SELECT order.dtorder
     , Count( DISTINCT order.fk_customer ) AS QtyCustomer
     , Count( DISTINCT order.id ) AS QtyOrder
     , Sum( order_item.qty ) AS TotalQtyItem
     , Sum( order.total ) AS TotalOrders
FROM order JOIN order_item ON order_item.fk_order = order.id
GROUP BY 1
ORDER BY 1


Ex.
ORDER
Id | dtorder    | fk_customer |   total
-----------------------------------------
 1 | 2007-01-01 |           1 |  100.00
 2 | 2007-01-01 |           1 |   30.00

order_item
fk_order |  qty  | fk_product
--------------------------------
 1       |    5  |           A
 1       |    2  |           B
 2       |    3  |           C

The query acctualy returns (as expected):

  dtorder  | QtyCustomer | QtyOrder  | TotalQtyItem | TotalOrders
------------------------------------------------------------------
2007-01-01 |          1  |        2  |           10 |      230.00


But I want

  dtorder  | QtyCustomer | QtyOrder  | TotalQtyItem | TotalOrders
------------------------------------------------------------------
2007-01-01 |          1  |        2  |           10 |      130.00


I just want to avoid to do, if possible, things like:

SELECT totals.dtorder
     , totals.QtyCustomer
     , totals.QtyOrder
     , totals.TotalQtyItem
     , Sum( order.total ) AS TotalOrders
FROM ( SELECT order.dtorder
             , Count( DISTINCT order.fk_customer ) AS QtyCustomer
             , Count( DISTINCT order.id ) AS QtyOrder
             , Sum( order_item.qty ) AS TotalQtyItem
        FROM order JOIN order_item ON order_item.fk_order = order.id
        GROUP BY 1 ) totals
     JOIN order ON order.dtorder = totals.dtorder
GROUP BY 1,2,3,4
ORDER BY totals.dtorder

I say this because it's seem a waste of effort just to sum a value that 
can be calculated on the same loop where postgresql will go on table 
order...
If someone can give me some hint I will apreciate.

Tanks in advance.

-- 
Luiz K. Matsumura
Plan IT Tecnologia Informática Ltda.