Message-ID: <4A81F186.6020701@pinpointresearch.com>
Date: Tue, 11 Aug 2009 15:32:38 -0700
From: Steve Crawford <scrawford@pinpointresearch.com>
User-Agent: Thunderbird 2.0.0.21 (X11/20090318)
MIME-Version: 1.0
To: Bor <dborovnik@gmail.com>
CC: pgsql-sql@postgresql.org
Subject: Re: Month/year between two dates
References: <24917400.post@talk.nabble.com>
In-Reply-To: <24917400.post@talk.nabble.com>
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 7bit

Bor wrote:
> Hi to all,
>
> I have a very simple question. Let's say that I have three records (id, date
> from, date to):
>
> 1     2009-01-01     2009-08-31
> 2     2009-08-01     2009-08-10
> 3     2009-08-11     2009-08-31
>
> Now I want to get records, "related" to a single month/year data (two
> integers). For 2009/08 (int1 = 2009, int2 = 8) I should get all three
> records, for 2009/05 only record 1, but for 2009/11 none of the records.
>
> Is there any simple way to do this? A query would do :).
>
> Thanks alot.
>   
Lots of ways. The following springs to mind but I'm sure there are 
simpler ways (I'm assuming the date_from and date_to are data-type date 
and you are stuck with using int for year and month).

Use date_trunc to convert any date in a month to the first of the month 
and the following should work (untested):
...
date_trunc('month', date_from) <= (int1::text || '-' || int2::text || 
'-1')::date and
date_trunc('month', date_to) >= (int1::text || '-' || int2::text || 
'-1')::date
...

Cheers,
Steve