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4+ messages / 4 participants
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* find and replace the string within a column
@ 2010-09-24 09:15 Nicholas I <nicholas.domnic.i@gmail.com>
2010-09-24 09:33 ` Re: find and replace the string within a column Jayadevan M <Jayadevan.Maymala@ibsplc.com>
2010-09-24 11:34 ` Re: find and replace the string within a column Craig Ringer <craig@postnewspapers.com.au>
0 siblings, 2 replies; 4+ messages in thread
From: Nicholas I @ 2010-09-24 09:15 UTC (permalink / raw)
To: pgsql-sql
Hi,
the data in my table, have a substring enclosed in parenthesis,
1. i want to replace the string with the brackets to null or any other
value.
2. remove the contents within brackets.
Example:
table name person:
name
------------------------------------
Samuel (S/o Sebastin )
-------------------------------------
remove the word within the brackets.
the output should be , Samuel.
the below one help's me to find the data within the two brackets.
SELECT name,(REGEXP_MATCHES(name, E'\\(.+?\\)'))[1] from person;
regexp_matches
------------------------------------
(S/o Sebastin )
-------------------------------------
-Nicholas I
^ permalink raw reply [nested|flat] 4+ messages in thread
* Re: find and replace the string within a column
2010-09-24 09:15 find and replace the string within a column Nicholas I <nicholas.domnic.i@gmail.com>
@ 2010-09-24 09:33 ` Jayadevan M <Jayadevan.Maymala@ibsplc.com>
1 sibling, 0 replies; 4+ messages in thread
From: Jayadevan M @ 2010-09-24 09:33 UTC (permalink / raw)
To: Nicholas I <nicholas.domnic.i@gmail.com>; +Cc: pgsql-sql; pgsql-sql-owner@postgresql.org
Hello,
> the below one help's me to find the data within the two brackets.
>
> SELECT name,(REGEXP_MATCHES(name, E'\\(.+?\\)'))[1] from person;
> regexp_matches
> ------------------------------------
> (S/o Sebastin )
> -------------------------------------
>
Trying to work with your code -
update table set name =
substr( name,1,strpos(name, (REGEXP_MATCHES(name, E'\\(.+?\\)')) )-1 ) ||
substr( name,strpos(name, (REGEXP_MATCHES(name, E'\\(.+?\\)')) ) + 1
,char_length(name))
I am trying to find what is there before the pattern and after the pattern
and concatenating them . Please see documentation for proper use of
substr,strpos,cahr_length etc.
Regards,
Jayadevan
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^ permalink raw reply [nested|flat] 4+ messages in thread
* Re: find and replace the string within a column
2010-09-24 09:15 find and replace the string within a column Nicholas I <nicholas.domnic.i@gmail.com>
@ 2010-09-24 11:34 ` Craig Ringer <craig@postnewspapers.com.au>
2010-09-24 14:39 ` Re: find and replace the string within a column Leif Biberg Kristensen <leif@solumslekt.org>
1 sibling, 1 reply; 4+ messages in thread
From: Craig Ringer @ 2010-09-24 11:34 UTC (permalink / raw)
To: Nicholas I <nicholas.domnic.i@gmail.com>; +Cc: pgsql-sql
On 24/09/2010 5:15 PM, Nicholas I wrote:
> Example:
> table name person:
>
> name
> ------------------------------------
> Samuel (S/o Sebastin )
> -------------------------------------
>
> remove the word within the brackets.
> the output should be , Samuel.
Can't you just regexp_replace, matching \([^)]+\) (in other words "an
open parenthisis, then a sequence of one or more of any character other
than a close parenthesis, followed by a close parentheis) and replacing
with an empty string ?
--
Craig Ringer
Tech-related writing at http://soapyfrogs.blogspot.com/
^ permalink raw reply [nested|flat] 4+ messages in thread
* Re: find and replace the string within a column
2010-09-24 09:15 find and replace the string within a column Nicholas I <nicholas.domnic.i@gmail.com>
2010-09-24 11:34 ` Re: find and replace the string within a column Craig Ringer <craig@postnewspapers.com.au>
@ 2010-09-24 14:39 ` Leif Biberg Kristensen <leif@solumslekt.org>
0 siblings, 0 replies; 4+ messages in thread
From: Leif Biberg Kristensen @ 2010-09-24 14:39 UTC (permalink / raw)
To: pgsql-sql
On Friday 24. September 2010 13.34.12 Craig Ringer wrote:
> On 24/09/2010 5:15 PM, Nicholas I wrote:
>
> > Example:
> > table name person:
> >
> > name
> > ------------------------------------
> > Samuel (S/o Sebastin )
> > -------------------------------------
> >
> > remove the word within the brackets.
> > the output should be , Samuel.
>
> Can't you just regexp_replace, matching \([^)]+\) (in other words "an
> open parenthisis, then a sequence of one or more of any character other
> than a close parenthesis, followed by a close parentheis) and replacing
> with an empty string ?
I'm doing a similar task, removing comments "hidden" within curly braces like
this:
str := REGEXP_REPLACE(str, '{.*?}', '', 'g');
No escaping needed at all.
regards,
Leif Biberg Kristensen
^ permalink raw reply [nested|flat] 4+ messages in thread
end of thread, other threads:[~2010-09-24 14:39 UTC | newest]
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-- links below jump to the message on this page --
2010-09-24 09:15 find and replace the string within a column Nicholas I <nicholas.domnic.i@gmail.com>
2010-09-24 09:33 ` Jayadevan M <Jayadevan.Maymala@ibsplc.com>
2010-09-24 11:34 ` Craig Ringer <craig@postnewspapers.com.au>
2010-09-24 14:39 ` Leif Biberg Kristensen <leif@solumslekt.org>
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