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To: "Fernando Hevia" <fhevia@ip-tel.com.ar>
cc: "'Emi Lu'" <emilu@encs.concordia.ca>, pgsql-sql@postgresql.org
Subject: Re: trim(both) problem? 
In-reply-to: <031701c8a717$c7458e90$8f01010a@iptel.com.ar> 
References: <4812402D.7080404@encs.concordia.ca>
	<20080425134220.S8763@megazone.bigpanda.com>
	<031701c8a717$c7458e90$8f01010a@iptel.com.ar>
Comments: In-reply-to "Fernando Hevia" <fhevia@ip-tel.com.ar>
	message dated "Fri, 25 Apr 2008 18:03:14 -0300"
Date: Fri, 25 Apr 2008 17:26:27 -0400
Message-ID: <751.1209158787@sss.pgh.pa.us>
From: Tom Lane <tgl@sss.pgh.pa.us>
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"Fernando Hevia" <fhevia@ip-tel.com.ar> writes:
>> Trim doesn't do what you think it does. The '<BR/>' in the 
>> above is not a string to remove it is a list of characters to 
>> remove.  Thus, the R is removed as it matches a character given.

> You could probably use instead:

> select replace('<BR/>ROI Engineering Inc.', '<BR/>', '')

That would zap occurrences in the middle of the string, though.
regexp_replace would be better since it'd allow anchoring the
pattern, eg

select regexp_replace('<BR/>ROI Engineering Inc.', '^<BR/>', '');
select regexp_replace('ROI Engineering Inc.<BR/>', '<BR/>$', '');

			regards, tom lane