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To get the column names, data types, and nullables of tables in the schema owned by MASTER_USER
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* To get the column names, data types, and nullables of tables in the schema owned by MASTER_USER
@ 2016-01-07 20:22 Eugene Yin <eugeneymail@ymail.com>
  2016-01-07 20:46 ` Re: To get the column names, data types, and nullables of tables in the schema owned by MASTER_USER Joe Conway <mail@joeconway.com>
  0 siblings, 1 reply; 2+ messages in thread

From: Eugene Yin @ 2016-01-07 20:22 UTC (permalink / raw)
  To: pgsql-sql

PostgreSQL ver: 9.4.5         OS: LinuxGOAL: To get the column names, data types, and nullables of tables in the schema owned by MASTER_USERIn Oracle, I can use the following statement:select 
    t.table_name,
    t.column_name,
    t.data_type,
    t.NULLABLE,
    (SELECT col.column_name
     FROM all_constraints cons, all_cons_columns col
     WHERE col.table_name = t.table_name
                        AND cons.constraint_type = 'P'
                        AND cons.constraint_name = col.constraint_name
                        AND cons.owner = col.owner and cons.owner = 'MASTER_USER'
    )  Primary_Key_Columnfrom user_tab_columns t;Now, I am on Postgres (9.4.5). How can I convert the above statement into the equivalent SQL  on Postgres?
ThanksEugene

^ permalink  raw  reply  [nested|flat] 2+ messages in thread

* Re: To get the column names, data types, and nullables of tables in the schema owned by MASTER_USER
  2016-01-07 20:22 To get the column names, data types, and nullables of tables in the schema owned by MASTER_USER Eugene Yin <eugeneymail@ymail.com>
@ 2016-01-07 20:46 ` Joe Conway <mail@joeconway.com>
  0 siblings, 0 replies; 2+ messages in thread

From: Joe Conway @ 2016-01-07 20:46 UTC (permalink / raw)
  To: Eugene Yin <eugeneymail@ymail.com>; pgsql-sql

On 01/07/2016 12:22 PM, Eugene Yin wrote:
> PostgreSQL ver: 9.4.5         OS: Linux
> GOAL: To get the column names, data types, and nullables of tables in
> the schema owned by MASTER_USER
> In Oracle, I can use the following statement:
> 
> |selectt.table_name,t.column_name,t.data_type,t.NULLABLE,(SELECTcol.column_name
> FROMall_constraints cons,all_cons_columns col WHEREcol.table_name
> =t.table_name ANDcons.constraint_type ='P'ANDcons.constraint_name
> =col.constraint_name ANDcons.owner =col.owner andcons.owner
> ='MASTER_USER')Primary_Key_Column|
> 
> from user_tab_columns t;
> Now, I am on Postgres (9.4.5). How can I convert the above statement
> into the equivalent SQL  on Postgres?

Rather than trying to rewrite that specific query, I'll leave that as an
exercise for you. But to help you get there, start psql with -E option.
Then you will see the queries behind all the meta-commands. E.g. to
describe table tenk1 in database regression:

# psql -E regression
psql (9.5rc1)
Type "help" for help.

regression=# \d tenk1

[...lots of SQL queries for describing the table...]

       Table "public.tenk1"
   Column    |  Type   | Modifiers
-------------+---------+-----------
 unique1     | integer |
 unique2     | integer |
 two         | integer |
 four        | integer |
 ten         | integer |
 twenty      | integer |
 hundred     | integer |
 thousand    | integer |
 twothousand | integer |
 fivethous   | integer |
 tenthous    | integer |
 odd         | integer |
 even        | integer |
 stringu1    | name    |
 stringu2    | name    |
 string4     | name    |
Indexes:
    "tenk1_hundred" btree (hundred)
    "tenk1_thous_tenthous" btree (thousand, tenthous)
    "tenk1_unique1" btree (unique1)
    "tenk1_unique2" btree (unique2)

HTH,

Joe




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PostgreSQL Support for Secure Enterprises
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