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Subject: Re: How best to work around the issue - regex string cannot contain
 brackets
From: Christophe Pettus <xof@thebuild.com>
In-Reply-To: 
 <CA+i5JwYi246WtbtgQQy5o7vhsj8DLqunAA4FW1m68NpLUp0gLg@mail.gmail.com>
Date: Thu, 3 Feb 2022 08:58:45 -0800
Cc: pgsql-sql <pgsql-sql@lists.postgresql.org>
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Message-Id: <7AF5777D-148E-4534-B442-891A911B0D2B@thebuild.com>
References: 
 <CA+i5JwYi246WtbtgQQy5o7vhsj8DLqunAA4FW1m68NpLUp0gLg@mail.gmail.com>
To: Shaozhong SHI <shishaozhong@gmail.com>
Archived-At: 
 <https://www.postgresql.org/message-id/7AF5777D-148E-4534-B442-891A911B0D2B%40thebuild.com>
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> On Feb 3, 2022, at 08:53, Shaozhong SHI <shishaozhong@gmail.com> =
wrote:
>=20
> One would consider the following would work, but it did not because =
the brackets.
> select regexp_matches('Department for Transport (Parking)', =
'Department for Transport (Parking)', 'g')
>=20
> Can anyone enlighten me?

You escape the ()s with a backslash:

xof=3D# select regexp_matches('Department for Transport (Parking)', =
'Department for Transport \(Parking\)', 'g');
             regexp_matches            =20
----------------------------------------
 {"Department for Transport (Parking)"}
(1 row)