X-Original-To: pgsql-sql-postgresql.org@localhost.postgresql.org Received: from localhost (unknown [200.46.204.144]) by svr1.postgresql.org (Postfix) with ESMTP id B671CD1B182 for ; Mon, 14 Jun 2004 15:08:11 -0300 (ADT) Received: from svr1.postgresql.org ([200.46.204.71]) by localhost (av.hub.org [200.46.204.144]) (amavisd-new, port 10024) with ESMTP id 49052-02 for ; Mon, 14 Jun 2004 18:07:15 +0000 (GMT) Received: from hotmail.com (bay8-f51.bay8.hotmail.com [64.4.27.51]) by svr1.postgresql.org (Postfix) with ESMTP id 6932BD1B1A9 for ; Mon, 14 Jun 2004 15:06:47 -0300 (ADT) Received: from mail pickup service by hotmail.com with Microsoft SMTPSVC; Mon, 14 Jun 2004 11:06:38 -0700 Received: from 69.65.137.210 by by8fd.bay8.hotmail.msn.com with HTTP; Mon, 14 Jun 2004 18:06:37 GMT X-Originating-IP: [69.65.137.210] X-Originating-Email: [el_vigia_ec@hotmail.com] X-Sender: el_vigia_ec@hotmail.com From: "Jaime Casanova" To: pgsql-sql@postgresql.org Subject: Re: query with =ALL Date: Mon, 14 Jun 2004 18:06:37 +0000 Mime-Version: 1.0 Content-Type: text/plain; format=flowed Message-ID: X-OriginalArrivalTime: 14 Jun 2004 18:06:38.0271 (UTC) FILETIME=[564D64F0:01C4523A] X-Virus-Scanned: by amavisd-new at hub.org X-Spam-Status: No, hits=1.1 tagged_above=0.0 required=5.0 tests=NO_DNS_FOR_FROM X-Spam-Level: * X-Archive-Number: 200406/115 X-Sequence-Number: 18060 On Mon, 14 Jun 2004, Jaime Casanova wrote: > i have an strange result here, i'm using 7.4.2 on redhat 8 > > i have a query like this > > SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor, > CPA.cpa_fechavencimiento > FROM rec_m_cuadropagos CPA, rec_m_rubro RUB > WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo > AND > CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo = > '2004-2005' AND > CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1 AND > CPA.cur_paralelo = ALL (SELECT cur_paralelo FROM aca_t_curso WHERE > ent_codigo = 1 AND > > sec_codigo = 1 AND > > ani_codigo = '2004-2005' AND > > cic_codigo = 1 AND > > esp_codigo = 0 AND > > cur_codigo = 1) > > that bring no values but if i do this (the same query without the =ALL part) > > SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor, > CPA.cpa_fechavencimiento > FROM rec_m_cuadropagos CPA, rec_m_rubro RUB > WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo > AND > CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo = > '2004-2005' AND > CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1 > > get a resultset, one would think that the =ALL subquery is filtering out > that rows but the cur_paralelo has same values in both sides > > select distinct cur_paralelo from rec_m_cuadropagos WHERE ent_codigo = 1 AND > > sec_codigo = 1 AND > > ani_codigo = '2004-2005' AND > > cic_codigo = 1 AND > > esp_codigo = 0 AND > > cur_codigo = 1 > intersect > SELECT cur_paralelo FROM aca_t_curso WHERE ent_codigo = 1 AND > > sec_codigo = 1 AND > > ani_codigo = '2004-2005' AND > > cic_codigo = 1 AND > > esp_codigo = 0 AND > > cur_codigo = 1 > > this query proves that its result is 'A', 'B', 'C' > > any idea, is something wrong in my thinking? AFAIK, The query isn't check all values that meet the other criteria against all values of the subquery but instead check the value from each row that meets the other criteria against all the values in the subquery. If the values in the subquery are distinct, it's not going to return true. Is there another solution instead the one i'm using can you help me in that? _________________________________________________________________ Add photos to your messages with MSN 8. Get 2 months FREE*. http://join.msn.com/?page=features/featuredemail