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Message-ID: <a55915760607211332ye89afd4m9bb2ad456fcef99b@mail.gmail.com>
Date: Fri, 21 Jul 2006 14:32:07 -0600
From: "Rodrigo De Leon" <rdeleonp@gmail.com>
To: pgsql-sql@postgresql.org
Subject: Re: CREATE TABLE AS inside of a function
In-Reply-To: <6EA72AC41F81D242A38AAF505523A94D022DF6@kappa.acrodex.net>
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References: <6EA72AC41F81D242A38AAF505523A94D022DF6@kappa.acrodex.net>

On 7/21/06, Kevin Nikiforuk <Kevin.Nikiforuk@acrodex.com> wrote:
> So now that I've got my loops working, on to my next newbie question.  I've created my function and in it, I want to loop through the results of a select and for each value of my loop counter, I want to create a new table, but I can't figure out how to use a variable in the name of the new table, see below.
>
> CREATE OR REPLACE FUNCTION rgio() RETURNS INTEGER as $$
> DECLARE
>         lv RECORD;
>
> BEGIN
>         FOR lv IN SELECT DISTINCT rg FROM ldevrg LOOP
>                 CREATE TABLE rgio_$lv AS
>                         SELECT ldev
>                         FROM ldevrg
>                         WHERE rg='$lv';
>         END LOOP;
> RETURN 1;
> END;
> $$ LANGUAGE plpgsql;
>
> Thanks,
> Kevin

See:
http://www.postgresql.org/docs/8.1/static/plpgsql-statements.html#PLPGSQL-STATEMENTS-EXECUTING-DYN

Regards,

Rodrigo