From: "Sabin Coanda" <sabin.coanda@deuromedia.ro>
Subject: Re: alias not applied
Date: Fri, 9 Feb 2007 18:35:35 +0200
Organization: Hub.Org Networking Services
Lines: 55
Message-ID: <eqi7se$1lvd$1@news.hub.org>
References: <eqi61k$1h2h$1@news.hub.org> <961.1171038340@sss.pgh.pa.us>
To: pgsql-sql@postgresql.org

You are right. I use "PostgreSQL 8.1.0 on i686-pc-mingw32, compiled by GCC 
gcc.exe (GCC) 3.4.2 (mingw-special)" on Windows.

But I just tried it on a newer version and it works well ( "PostgreSQL 8.1.4 
on i686-redhat-linux-gnu, compiled by GCC gcc (GCC) 4.0.2 20051125 (Red Hat 
4.0.2-8)" ).

Thanks a lot,
Sabin


"Tom Lane" <tgl@sss.pgh.pa.us> wrote in message 
news:961.1171038340@sss.pgh.pa.us...
> "Sabin Coanda" <sabin.coanda@deuromedia.ro> writes:
>> I have two queries:
>
>> 1. SELECT i AS "PK_ID", d AS "Deleted" FROM ( SELECT 52 AS i, true AS 
>>   ) x
>> ORDER BY i
>> 2. SELECT i AS "PK_ID", d AS "Deleted" FROM ( SELECT 49 AS i, true AS d
>> UNION SELECT 51 AS i, true AS d  ) x ORDER BY i
>
>> The first returns the columns "PK_ID", "Deleted"
>> The second returns the columns i, d.
>
> Works for me:
>
> regression=# SELECT i AS "PK_ID", d AS "Deleted" FROM ( SELECT 52 AS i, 
> true AS d  ) x ORDER BY i;
> PK_ID | Deleted
> -------+---------
>    52 | t
> (1 row)
>
> regression=# SELECT i AS "PK_ID", d AS "Deleted" FROM ( SELECT 49 AS i, 
> true AS d UNION SELECT 51 AS i, true AS d  ) x ORDER BY i;
> PK_ID | Deleted
> -------+---------
>    49 | t
>    51 | t
> (2 rows)
>
> regression=#
>
> What PG version are you using, exactly?
>
> regards, tom lane
>
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