Message-ID: <m2osn-brf.ln1@my-pc.ntlworld.com>
From: David W Noon <dwnoon@spamtrap.ntlworld.com>
Subject: Re: EASY QUESTION!!
References: <1cf4c899.0304270003.244d1ce@posting.google.com>
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Date: Sun, 27 Apr 2003 11:30:13 +0100
Organization: ntl Cablemodem News Service
To: pgsql-sql@postgresql.org

On Sunday 27 Apr 2003 09:03 in
<1cf4c899.0304270003.244d1ce@posting.google.com>, dvsangel
(dvsangel@dodo.com.au) wrote:

> a column in one of my tables contains dates in the format yyyy-mm-dd
> From these dates I need to find out which dates are sundays.

I assume that the column is a DATE rather than a CHAR(10).

If so, the EXTRACT(DOW FROM ...) function should give you what you want. A
value of 0 means Sunday.

If your column is actually a CHAR(10) then coerce it to being a DATE as you
invoke EXTRACT() as above. YMMV.

For example:

SELECT * FROM some_table
   WHERE EXTRACT(DOW FROM date_column) = 0;

or:

SELECT * FROM some_table
   WHERE EXTRACT(DOW FROM CAST(char_column AS DATE)) = 0;

See section 4.8.1 in the PostgreSQL User's Guide for more details. [At least
that's where it is in my copy.]

-- 
Regards,

Dave
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