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From: Tom Lane <tgl@sss.pgh.pa.us>
To: Holger Jakobs <holger@jakobs.com>
Cc: pgsql-admin@lists.postgresql.org
Cc: n2029@ndensan.co.jp
Subject: Re: About Unicode IVS
Date: Tue, 29 Mar 2022 06:25:56 -0400
Message-ID: <1107956.1648549556@sss.pgh.pa.us> (raw)
In-Reply-To: <15e893e2-1237-27f4-58ba-5ea59499fa3d@jakobs.com>
References: <00e201d8431c$cb38eb40$61aac1c0$@ndensan.co.jp>
	<CAKFQuwYCTmp5t5_7n+qRoKZArnBvv309CSi4XVdONXxQL6OX0Q@mail.gmail.com>
	<00f601d84326$5367cf00$fa376d00$@ndensan.co.jp>
	<006501d84350$37bae6f0$a730b4d0$@msym.fr>
	<012c01d84353$1f8a8d30$5e9fa790$@ndensan.co.jp>
	<15e893e2-1237-27f4-58ba-5ea59499fa3d@jakobs.com>

Holger Jakobs <holger@jakobs.com> writes:
> It's totally correct that the two characters are still two characters.
> You would have to normalize the string first, so that the combination 
> becomes one character.

Yeah.  In principle the normalize() function ought to do this for
you.  But it doesn't seem to shorten the given example for me;
I'm not sure if that means the example is incorrect, or if it's
a bug in normalize().

u8=# select octet_length(U&'\+008FBA' || U&'\+0E0102');
 octet_length 
--------------
            7
(1 row)

u8=# select octet_length(normalize(U&'\+008FBA' || U&'\+0E0102'));
 octet_length 
--------------
            7
(1 row)

			regards, tom lane

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