From: Pawel Socha <pawel.socha@gmail.com>
To: ss_postgres <ss.postgres@gmail.com>
Cc: pgsql-admin@postgresql.org
Subject: Re: How to find the position of a characted in a string
Date: Mon, 8 Dec 2008 08:14:22 +0100
Message-ID: <cc4f12900812072314r161e191vc9d2d0364f187c89@mail.gmail.com> (raw)
In-Reply-To: <6c1264780812072230v6d89cbf4hf618c035d98319b4@mail.gmail.com>
References: <6c1264780812072230v6d89cbf4hf618c035d98319b4@mail.gmail.com>
2008/12/8 ss_postgres <ss.postgres@gmail.com>:
> Hi,
>
> I am trying to find the position of a character in a string which appears
> multiple times.
>
> The POSITION function returns the position of the character when it first
> occurs.
>
> For eg:
>
> select position ( ' ' in 'Hi How are you');
>
> This returns the result as "3".
>
>
> But i need to result to be
> 3
> 7
> 11
>
>
> Can anyone please let me know what would be the best way to do this.
>
> Thanks
>
My first things:
merlin=> select distinct(x.case) from (select (case when substring('Hi
How are you' from r for 1) = ' ' then r else null end) from
generate_series(0, length('Hi How are you')) as r) as x;
case
------
3
7
11
--
Pawel Socha
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To: pgsql-admin@postgresql.org
Cc: pawel.socha@gmail.com, ss.postgres@gmail.com
Subject: Re: How to find the position of a characted in a string
In-Reply-To: <cc4f12900812072314r161e191vc9d2d0364f187c89@mail.gmail.com>
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