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From: Vik Fearing <vik@postgresfriends.org>
To: Tom Lane <tgl@sss.pgh.pa.us>
Cc: pgsql-bugs <pgsql-bugs@postgresql.org>
Subject: Re: Wrong result with constant quals
Date: Fri, 4 Nov 2022 00:56:56 +0100
Message-ID: <309137b4-9b48-5952-c6e1-0fa7007d0419@postgresfriends.org> (raw)
In-Reply-To: <2193245.1667518580@sss.pgh.pa.us>
References: <f895925a-f2da-5651-af71-21cd8238b9f5@postgresfriends.org>
	<2193245.1667518580@sss.pgh.pa.us>

On 11/4/22 00:36, Tom Lane wrote:
> Vik Fearing <vik@postgresfriends.org> writes:
>> The following query returns a wrong result, in my opinion.
> 
>> postgres=# select 1 where false having true;
>>    ?column?
>> ----------
>>           1
>> (1 row)
> 
>> The correct result should be zero rows.
> 
> No, I don't think so.  The presence of HAVING without GROUP BY makes
> this act like a query with an aggregate function and no GROUP BY: you
> get a single grouped row, regardless of what the input is.  There's a
> reasonably clear specification of that in SQL92 7.8 <having clause>:

SQL92?  wut?

>           1) Let T be the result of the preceding <from clause>, <where
>              clause>, or <group by clause>. If that clause is not a <group
>              by clause>, then T consists of a single group and does not have
>              a grouping column.
> 
> "A single group" is not "no groups".
> 
> Later SQL versions define this by reference to "GROUP BY ()", but
> I think the effect is the same.

I allowed for this by saying it could be a single group with no rows if 
you preferred to look at it that way.

This does not explain why the WHERE FALSE is being ignored and producing 
rows.
-- 
Vik Fearing






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