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* Re: Regression in Postgres 17?
@ 2024-10-22 16:03 Adrian Klaver <[email protected]>
2024-10-22 16:12 ` Re: Regression in Postgres 17? Tom Lane <[email protected]>
0 siblings, 1 reply; 2+ messages in thread
From: Adrian Klaver @ 2024-10-22 16:03 UTC (permalink / raw)
To: Colin 't Hart <[email protected]>; [email protected]
On 10/22/24 08:54, Colin 't Hart wrote:
> Hi,
>
> This works in Postgres 15:
>
> pg15> create function json_test(out value text, out json jsonb)
> returns record
> language sql
> as
> $$
> select null::text, null::jsonb;
> $$
> ;
> CREATE FUNCTION
> pg15> select * from json_test();
> ┌───────┬──────┐
> │ value │ json │
> ├───────┼──────┤
> │ │ │
> └───────┴──────┘
> (1 row)
>
>
> In Postgres 17 trying to create the function yields an error:
>
> pg17> create function json_test(out value text, out json jsonb)
> returns record
> language sql
> as
> $$
> select null::text, null::jsonb;
> $$
> ;
> ERROR: syntax error at or near "jsonb"
> LINE 1: create function json_test(out value text, out json jsonb)
>
>
> Am I doing something wrong? Or is this a regression?
Yes you are doing something wrong, naming an argument with a type
name(json) is not a good idea. Guessing you got caught by this:
https://www.postgresql.org/docs/16/sql-keywords-appendix.html
JSON non-reserved reserved
https://www.postgresql.org/docs/17/sql-keywords-appendix.html
JSON non-reserved (cannot be function or type) reserved
> Thanks,
>
> Colin
--
Adrian Klaver
[email protected]
^ permalink raw reply [nested|flat] 2+ messages in thread
* Re: Regression in Postgres 17?
2024-10-22 16:03 Re: Regression in Postgres 17? Adrian Klaver <[email protected]>
@ 2024-10-22 16:12 ` Tom Lane <[email protected]>
0 siblings, 0 replies; 2+ messages in thread
From: Tom Lane @ 2024-10-22 16:12 UTC (permalink / raw)
To: Adrian Klaver <[email protected]>; +Cc: Colin 't Hart <[email protected]>; [email protected]
Adrian Klaver <[email protected]> writes:
>> In Postgres 17 trying to create the function yields an error:
>>
>> pg17> create function json_test(out value text, out json jsonb)
>> returns record
>> ...
>> ERROR: syntax error at or near "jsonb"
>> LINE 1: create function json_test(out value text, out json jsonb)
>>
>> Am I doing something wrong? Or is this a regression?
> Yes you are doing something wrong, naming an argument with a type
> name(json) is not a good idea.
The actual problem is that the SQL standards committee invented
some bizarre syntax that we couldn't parse without making JSON
a partially-reserved word. It still works as a type name, but
in this particular syntax where it's not initially clear which
names are type names, you lose. Double-quote the argument name,
or name it something other than "json".
regards, tom lane
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