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From: Tom Lane <tgl@sss.pgh.pa.us>
To: Sergey Shinderuk <s.shinderuk@postgrespro.ru>
Cc: Thomas Munro <thomas.munro@gmail.com>
Cc: pgsql-hackers <pgsql-hackers@postgresql.org>
Subject: Re: pg_preadv() and pg_pwritev()
Date: Thu, 14 Jan 2021 13:31:40 -0500
Message-ID: <1419199.1610649100@sss.pgh.pa.us> (raw)
In-Reply-To: <1418166.1610647514@sss.pgh.pa.us>
References: <CA+hUKGJA+u-220VONeoREBXJ9P3S94Y7J+kqCnTYmahvZJwM=g@mail.gmail.com>
	<341497.1608420857@sss.pgh.pa.us>
	<CA+hUKG+7UHOH2VGRwvJZ=vXUH9pRA-Tp3gP9EHgtjwzjyfOpWg@mail.gmail.com>
	<20201220224040.evr5pduibvm6dze5@alap3.anarazel.de>
	<CA+hUKG+TCoareSYcAu05yaMh9eUck6Hd8FQZt5VEvotNs3YOMQ@mail.gmail.com>
	<CA+hUKGJ8Ww_fjzUzthdxUF6W3JQ3r=a1hWX7Fcfq9uEndZ_+GQ@mail.gmail.com>
	<CA+hUKGL9XFxM0ZO8ZADYJepSmjywknhnDkKSEttfmn2j9fg0BQ@mail.gmail.com>
	<ed3b8e5d-0da8-6ebd-fd1c-e0ac80a4b204@postgrespro.ru>
	<CA+hUKG+L573j4=XWv6S+r-687Yxn0FyXhtObH9_P-Nu_atL2pQ@mail.gmail.com>
	<448b3cb5-0ba0-6dc5-63c7-789e4eebc40b@postgrespro.ru>
	<1283127.1610554395@sss.pgh.pa.us>
	<1286060.1610558607@sss.pgh.pa.us>
	<1297389.1610562046@sss.pgh.pa.us>
	<1341608.1610580122@sss.pgh.pa.us>
	<c2e08e38-e4bd-780d-62df-4a33b537b75e@postgrespro.ru>
	<d90658e6-490e-db57-cd64-98868abe79cd@postgrespro.ru>
	<1410650.1610638974@sss.pgh.pa.us>
	<b2586af5-866f-8290-f068-046fbd1a01b8@postgrespro.ru>
	<1418166.1610647514@sss.pgh.pa.u! s>

I wrote:
> It seems like the more productive approach would be to try to identify
> the right sysroot to use.  I wonder if there is some less messy way
> to find out the compiler's default sysroot than to scrape it out of
> -v output.

This is, of course, not terribly well documented by Apple.  But
Mr. Google suggests that "xcrun --show-sdk-path" might serve.
What does that print for you?

			regards, tom lane





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  To: pgsql-hackers@postgresql.org
  Cc: tgl@sss.pgh.pa.us, s.shinderuk@postgrespro.ru, thomas.munro@gmail.com
  Subject: Re: pg_preadv() and pg_pwritev()
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