From: Jeff Davis <pgsql@j-davis.com>
To: Paul Jungwirth <pj@illuminatedcomputing.com>
To: Pgsql Hackers <pgsql-hackers@postgresql.org>
Subject: Re: range_agg
Date: Mon, 01 Jul 2019 15:38:30 -0700
Message-ID: <ba323e489b98029be5ba2d5c5cbc99795f333f48.camel@j-davis.com> (raw)
In-Reply-To: <16d71dc8-34cf-5ebd-1ce5-ccd93c0a14f9@illuminatedcomputing.com>
References: <16d71dc8-34cf-5ebd-1ce5-ccd93c0a14f9@illuminatedcomputing.com>
On Fri, 2019-05-03 at 15:56 -0700, Paul Jungwirth wrote:
> Hello,
>
> I wrote an extension to add a range_agg function with similar
> behavior
> to existing *_agg functions, and I'm wondering if folks would like
> to
> have it in core? Here is the repo:
> https://github.com/pjungwir/range_agg
This seems like a very useful extension, thank you.
For getting into core though, it should be a more complete set of
related operations. The patch is implicitly introducing the concept of
a "multirange" (in this case, an array of ranges), but it's not making
the concept whole.
What else should return a multirange? This patch implements the union-
agg of ranges, but we also might want an intersection-agg of ranges
(that is, the set of ranges that are subranges of every input). Given
that there are other options here, the name "range_agg" is too generic
to mean union-agg specifically.
What can we do with a multirange? A lot of range operators still make
sense, like "contains" or "overlaps"; but "adjacent" doesn't quite
work. What about new operations like inverting a multirange to get the
gaps?
Do we want to continue with the array-of-ranges implementation of a
multirange, or do we want a first-class multirange concept that might
eliminate the boilerplate around defining all of these operations?
If we have a more complete set of operators here, the flags for
handling overlapping ranges and gaps will be unnecessary.
Regards,
Jeff Davis
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To: pgsql-hackers@postgresql.org
Cc: pgsql@j-davis.com, pj@illuminatedcomputing.com
Subject: Re: range_agg
In-Reply-To: <ba323e489b98029be5ba2d5c5cbc99795f333f48.camel@j-davis.com>
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