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* ISO8601 Time and ODBC
@ 2000-09-06 15:23 Carl Shelbourne <Carl.Shelbourne@marconi.com>
2000-09-11 15:38 ` Re: ISO8601 Time and ODBC Thomas Lockhart <lockhart@alumni.caltech.edu>
0 siblings, 1 reply; 2+ messages in thread
From: Carl Shelbourne @ 2000-09-06 15:23 UTC (permalink / raw)
To: pgsql-interfaces
I am trying to get a fully qualified ISO8601 string
yyyy-mm-dd hh:mm:ss.h+MM:SS where MM:SS are the time offsets to GMT.
I am Using Postgres 7, UNIXodbc.
Using psql to query the table I get the time as:
2000-08-30 12:00:00+01
But the query via ODBC returns a SQL_C_TYPE_TIMESTAMP struct defined as
SQL_C_TYPE_TIMESTAMP SQL_TIMESTAMP_STRUCT struct tagTIMESTAMP_STRUCT {
SQLSMALLINT year;
SQLUSMALLINT month;
SQLUSMALLINT day;
SQLUSMALLINT hour;
SQLUSMALLINT minute;
SQLUSMALLINT second;
SQLUINTEGER fraction;
} TIMESTAMP_STRUCT;
The problem I have is I am working across timezones and I need to know the time
offset to GMT. Currently I am in the UK on BST +01:00, which psql seems to
return,
Does anybody know how I can get the offset to the time returned by Postgres
using ODBC??, this is not included in the above struct.
Thanks
Carl
^ permalink raw reply [nested|flat] 2+ messages in thread
* Re: ISO8601 Time and ODBC
2000-09-06 15:23 ISO8601 Time and ODBC Carl Shelbourne <Carl.Shelbourne@marconi.com>
@ 2000-09-11 15:38 ` Thomas Lockhart <lockhart@alumni.caltech.edu>
0 siblings, 0 replies; 2+ messages in thread
From: Thomas Lockhart @ 2000-09-11 15:38 UTC (permalink / raw)
To: Carl Shelbourne <Carl.Shelbourne@marconi.com>; +Cc: pgsql-interfaces
> Does anybody know how I can get the offset to the time returned by Postgres
> using ODBC??, this is not included in the above struct.
select date_part('timezone', timefield)
will do it, so just return another column in the query.
- Thomas
^ permalink raw reply [nested|flat] 2+ messages in thread
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2000-09-06 15:23 ISO8601 Time and ODBC Carl Shelbourne <Carl.Shelbourne@marconi.com>
2000-09-11 15:38 ` Thomas Lockhart <lockhart@alumni.caltech.edu>
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