From: Tod McQuillin <devin@spamcop.net>
To: Randall Perry <rgp@systame.com>
Cc: pgsql-interfaces@postgresql.org
Subject: Re: [GENERAL] Var substitution in SELECT statements
Date: Tue, 24 Apr 2001 21:01:56 -0500 (CDT)
Message-ID: <Pine.GSO.4.31.0104242058350.4814-100000@sysadmin> (raw)
In-Reply-To: <B70A4D23.A28D%rgp@systame.com>
On Mon, 23 Apr 2001, Randall Perry wrote:
> This works:
> $res = $conn->exec("select cust, contact, user_name, email from $t where
> user_name = a1a");
>
> This doesn't:
> $c = "a1a";
> $res = $conn->exec("select cust, contact, user_name, email from $t where
> user_name = $c");
>
> and returns the error:
> Attribute 'a1a' not found
>
> How do you do var substitution with the Pg module in Perl?
First, I would highly recommend you investigate the perl DBI abd DBD::Pg
modules -- they handle variable placeholders quite efficiently and
correctly.
But for your problem above, surely you must use single quotes around any
string you include as a literal in an SQL query.
$res = $conn->exec("select cust, contact, user_name, email from $t
where user_name = '$c'");
--
Tod McQuillin
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To: pgsql-interfaces@postgresql.org
Cc: devin@spamcop.net, rgp@systame.com
Subject: Re: [GENERAL] Var substitution in SELECT statements
In-Reply-To: <Pine.GSO.4.31.0104242058350.4814-100000@sysadmin>
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