From: terry@ashtonwoodshomes.com
To: 'Masaru Sugawara' <rk73@sea.plala.or.jp>
Cc: pgsql-sql@postgresql.org
Subject: Re: query optimization question
Date: Wed, 6 Nov 2002 12:10:33 -0500
Message-ID: <003f01c285b7$6b3c0480$2766f30a@development.greatgulfhomes.com> (raw)
In-Reply-To: <20021107014333.F0D0.RK73@sea.plala.or.jp>
That looks really promising as a possibility, however I think you intended
to add a group by clause.
Terry Fielder
Network Engineer
Great Gulf Homes / Ashton Woods Homes
terry@greatgulfhomes.com
> -----Original Message-----
> From: Masaru Sugawara [mailto:rk73@sea.plala.or.jp]
> Sent: Wednesday, November 06, 2002 11:44 AM
> To: terry@ashtonwoodshomes.com
> Cc: pgsql-sql@postgresql.org
> Subject: Re: [SQL] query optimization question
>
>
> On Wed, 6 Nov 2002 09:01:49 -0500
> <terry@ashtonwoodshomes.com> wrote:
>
> > If anyone can see a way to do a group by to do this, then I
> will be happy to
> > hear about it, because currently the resultset has to do a separate
> > (sequential or index) scan of the deficiencies table. The
> only way I can
> > see to do a group by would be to break out the aging categories into
> > separate queries, but that wins me nothing because each
> query then does its
> > own scan...
> >
> > The expected simplified output of this query looks like this:
> > Project <30 30-60 >=60 lot total <30
> 30-60 >=60 def total
> > X 1 2 1 4 5 10 5
> 20 (if X had 4 lots, each of 5 deficiencies)
> > Y 1 1 0 2 3 3 0
> 6 (each has eg 3 deficiencies in project Y)
> >
>
>
> The following query may be one of the ways, but I cannot
> confirm whether
> it goes well or not.
>
>
> SELECT
> project_id,
> marketing_name,
> COUNT(lots.lot_id) AS def_count,
> COUNT(CASE WHEN dt.days_old_start_date < {d '2002-10-07'}
> THEN lots.lot_id ELSE NULL END) AS
> def_count_less_30,
> COUNT(CASE WHEN dt.days_old_start_date >= {d '2002-10-07'}
> AND dt.days_old_start_date < {d
> '2002-09-07'}
> THEN lots.lot_id ELSE NULL END) AS
> def_count_30_60,
> COUNT(CASE WHEN dt.days_old_start_date >= {d '2002-09-07'}
> AND dt.days_old_start_date < {d
> '2002-08-08'}
> THEN lots.lot_id ELSE NULL END) AS
> def_count_60_90,
> COUNT(CASE WHEN dt.days_old_start_date >= {d '2002-08-08'}
> THEN lots.lot_id ELSE NULL END) AS
> def_count_greater_90,
> COUNT(DISTINCT(CASE WHEN
> dt.days_old_start_date <
> {d '2002-10-07'}
> THEN lots.lot_id ELSE NULL END ))
> AS lot_count_less_30,
> COUNT(DISTINCT(CASE WHEN
> dt.days_old_start_date >=
> {d '2002-10-07'}
> AND dt.days_old_start_date < {d
> '2002-09-07'}
> THEN lots.lot_id ELSE NULL END ))
> AS lot_count_30_60,
> COUNT(DISTINCT(CASE WHEN
> dt.days_old_start_date >=
> {d '2002-09-07'}
> AND dt.days_old_start_date < {d
> '2002-08-08'}
> THEN lots.lot_id ELSE NULL END ))
> AS lot_count_60_90,
> COUNT(DISTINCT(CASE WHEN
> dt.days_old_start_date >=
> {d '2002-08-08'}
> THEN lots.lot_id ELSE NULL END ))
> AS lot_count_greater_90,
> COUNT(DISTINCT lots.lot_id) AS lot_count
> FROM
> (SELECT * FROM deficiency_table
> WHERE assigned_supplier_id = '101690') AS dt,
> (SELECT * FROM deficiency_status,
> WHERE ds.is_outstanding) AS ds,
> (SELECT * FROM projects
> WHERE proj.division_id = 'GGH') AS proj
> lots
> WHERE
> dt.lot_id = lots.lot_id
> AND lots.division_id = proj.division_id
> AND lots.project_id = proj.project_id
> AND dt.deficiency_status_id = ds.deficiency_status_id
> AND NOT EXISTS
> (SELECT 1 FROM menu_group_projects
> WHERE menu_code = 'WA'
> AND division_id = proj.division_id
> AND project_id = proj.project_id
> AND status = 'I')
> ORDER BY proj.project_id
>
>
>
>
> Regards,
> Masaru Sugawara
>
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To: pgsql-sql@postgresql.org
Cc: terry@ashtonwoodshomes.com, rk73@sea.plala.or.jp
Subject: Re: query optimization question
In-Reply-To: <003f01c285b7$6b3c0480$2766f30a@development.greatgulfhomes.com>
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