From: Oliveiros Cristina <oliveiros.cristina@marktest.pt>
To: Loredana Curugiu <loredana.curugiu@gmail.com>
To: Oliveiros Cristina <oliveiros.cristina@gmail.com>
To: pgsql-novice@postgresql.org
To: pgsql-sql@postgresql.org
Subject: Re: [SQL] JOIN
Date: Tue, 5 Jun 2007 16:00:27 +0100
Message-ID: <012601c7a782$40dd4ae0$ec5a3d0a@marktestcr.marktest.pt> (raw)
References: <1c23c8e70706050111i5ba672d6j78bd9afa4b786616@mail.gmail.com>
<1c23c8e70706050426y12d567ban70ffdafb75808e0e@mail.gmail.com>
<f54607780706050619u2e2c12dpcc3a4414370e0636@mail.gmail.com>
<1c23c8e70706050708h6c5b708dpc2f53ff76a73740c@mail.gmail.com>
<1c23c8e70706050715y45688e12n90fcf8cecd84b251@mail.gmail.com>
<f54607780706050730i23979220t97bdef2e199c09d6@mail.gmail.com>
<1c23c8e70706050746v10dfaa6bn88f2f4ef8cd4b057@mail.gmail.com>
And , still, in your query, you are grouping by A.dates... is there any reason for this that I am missing ?
SELECT SUM(A.count),
A.theme,
A.receiver,
A.dates
FROM my_table A
INNER JOIN my_table B
ON A.theme=B.theme
AND A.receiver=B.receiver
AND A.date=ANY(B.dates)
GROUP BY A.theme,A.receiver, A.dates;
If the dates column works as a "discriminator" to see if the row should be considered or not,
maybe this would work
SELECT SUM(count), theme,receiver,date
FROM my_table
WHERE date=ANY(dates)
GROUP BY theme,receiver,date ;
But I don't know, do you need to include the column "dates" on output ?
Best,
Oliveiros
From: Loredana Curugiu
To: Oliveiros Cristina ; pgsql-novice@postgresql.org ; pgsql-sql@postgresql.org
Sent: Tuesday, June 05, 2007 3:46 PM
Subject: Re: [SQL] JOIN
Hmm...try to add the following clause to your INNER JOIN
AND A.date = B.Date
Like this :
INNER JOIN view_sent_messages B
ON A.theme=B.theme
AND A.receiver=B.receiver
AND A.date = b.Date
AND B.date=ANY (A.dates)
Doesn't work. I get the result
sum | theme | receiver | dates
-----+--------+--------------+--------------------------------------------------------------------------------
3 | CRIS | +40741775622 | {2007-06-01,2007-06-02,2007-06-03,2007-06-04,2007-06-05,2007-06-06,2007-06-07}
1 | CRIS | +40741775622 | {2007-06-02,2007-06-03,2007-06-04,2007-06-05,2007-06-06,2007-06-07,2007-06-08}
1 | CRIS | +40741775622 | {2007-06-03,2007-06-04,2007-06-05,2007-06-06,2007-06-07,2007-06-08,2007-06-09}
9 | CRIS | +40741775622 | {2007-06-04,2007-06-05,2007-06-06,2007-06-07,2007-06-08,2007-06-09,2007-06-10}
4 | LIA | +40741775621 | {2007-06-01,2007-06-02,2007-06-03,2007-06-04,2007-06-05,2007-06-06}
2 | LIA | +40741775621 | {2007-06-02,2007-06-03,2007-06-04,2007-06-05,2007-06-06,2007-06-07}
2 | LIA | +40741775621 | {2007-06-03,2007-06-04,2007-06-05,2007-06-06,2007-06-07,2007-06-08}
4 | LIA | +40741775621 | {2007-06-04,2007-06-05,2007-06-06,2007-06-07,2007-06-08,2007-06-09}
Which is not correct. The wrong values ( red colored ) remain as before
adding the clause. And now it is summed the counter's values per day
( first day of dates array ).
I have not your data here, so I am not sure if it'll work.
Also, Ive never worked with vectors on Postgres. I am assuming ANY() returns true if B.date is on the vector A.dates, is this correct??
Correct.
Regards,
Loredana
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To: pgsql-sql@postgresql.org
Cc: oliveiros.cristina@marktest.pt, loredana.curugiu@gmail.com, oliveiros.cristina@gmail.com, pgsql-novice@postgresql.org
Subject: Re: [SQL] JOIN
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