From: Edward W. Rouse <erouse@comsquared.com>
To: pgsql-sql@postgresql.org
Subject: group by day
Date: Thu, 24 May 2007 14:49:47 -0400
Message-ID: <04c201c79e34$4e3877c0$143c520a@ntc2s.comsquared.com> (raw)
I have an audit table that I am trying to get a count of the number of distinct entries per day by the external table key field. I
can do a
select count(distinct(id)) from audit where timestamp >= '01-may-2007'
and get a total count. What I need is a way to group on each day and get a count per day such that the result would be something
like
date count
01-may-2007 107
02-may-2007 215
03-may-2007 96
04-may-2007 0
I would prefer the 0 entries be included but can live without them. Thanks.
Oh, postgres 7.4 by the way.
Edward W. Rouse
ComSquared Systems, Inc.
770-734-5301
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Reply to all the recipients using the --to and --cc options:
reply via email
To: pgsql-sql@postgresql.org
Cc: erouse@comsquared.com
Subject: Re: group by day
In-Reply-To: <04c201c79e34$4e3877c0$143c520a@ntc2s.comsquared.com>
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
This inbox is served by DDX for PostgreSQL; see mirroring instructions
for how to clone and mirror all data and code used for this inbox